The volume of a rod can be calculated using the formula for the volume of a cylinder, which is V = πr^2h, where r is the radius of the rod and h is the height (or length) of the rod. If the rod has a constant cross-sectional area, the volume can also be calculated by multiplying the cross-sectional area by the length of the rod. The unit of measurement for the volume of a rod would be cubic units, such as cubic inches or cubic centimeters.
To calculate the weight of an aluminum rod in inches, you would need to know the density of aluminum (which is about 0.098 lbs/in^3) and the volume of the rod (which can be calculated using its length and diameter). You can then multiply the volume by the density to find the weight of the aluminum rod.
Submerge the object in a known volume of liquid within a container with graduation markings. Carefully turn the object to release and trapped gases from concavities. Measure the new volume of liquid with the object submerged and subtract the original volume. The difference is the volume of the irregularly shaped object. If the object is buoyant, choose a lower density liquid or hold the object beneath the surface with a rod or rods, noting the length of rod(s) submerged at the time of the second fluid measurement, then subtract the volume of rod submerged from the difference in the two fluid volumes.
If the diameter of the rod is increased but the oil flow remains the same, the retraction speed of the cylinder rod will decrease. This is because a larger diameter rod requires more volume of oil to fill, resulting in slower movement when the same amount of oil is flowing through.
You look up the density of steel, then calculate the volume of the rod, then multiply the density by the volume to find the mass of the rod. To find the weight of the rod, you multiply it's mass by gravataional acceleration.The rod has a cross sectional area of Pi x (0.008 / 2)2 m2Volume of the rod = 1 x 5.027x10-5Steel has a density of approx. 7850 kg/m3.Mass = Density x VolumeMass = 7850 x 5.027x10-5Mass = 0.395 kgWeight = 0.398 x 9.81Weight = 3.871 Newtons
To calculate the weight of the steel rod, you first need to find the volume using the formula for the volume of a cylinder (V = πr^2h, where r is the radius and h is the height). Then, you can calculate the weight by multiplying the volume by the density of steel, typically around 7850 kg/m^3. Finally, convert the volume into meters before calculating the weight to ensure consistent units.
To calculate the weight of an aluminum rod in inches, you would need to know the density of aluminum (which is about 0.098 lbs/in^3) and the volume of the rod (which can be calculated using its length and diameter). You can then multiply the volume by the density to find the weight of the aluminum rod.
weight of all steel can be calculated by multiplying unit volume with density.
pi*radius2*length in cubic units
Weight = Volume times Density To answer this question the density of the rod has to be known, probably in Kg per Cubic Meter ( kg/m3) Volume of rod is Cross-sectional Area times Length Area for Square section rod is 19/1000 times 19/1000 = 0.000361 square meters Length is 1 meter Therefore volume is 0.000361 cubic meters Area for Round rod section is π*D squared / 4 or 22/7 * 19/1000*19/1000 / 4 = 0.000284 square meters. Length is 1 meter therefor Volume is 0.000284 cubic meters Weight is Volume times Density All units have to be compatible!
In general the volume of any cone is: 1/3*pi*radius2*height
It depends on the dimensions of the cubic rod. To calculate the volume of a cube, you would need to know the length of one side (in feet) and then calculate the cube of that length (side length x side length x side length). The result will give you the volume of the cubic rod in cubic feet.
A cubic rod is a shape that has equal length, width, and height. Therefore, to find the volume in cubic feet, you need to multiply the length, width, and height together. For example, if the dimensions of the rod are 1 foot x 1 foot x 1 foot, then the volume would be 1 cubic foot.
Submerge the object in a known volume of liquid within a container with graduation markings. Carefully turn the object to release and trapped gases from concavities. Measure the new volume of liquid with the object submerged and subtract the original volume. The difference is the volume of the irregularly shaped object. If the object is buoyant, choose a lower density liquid or hold the object beneath the surface with a rod or rods, noting the length of rod(s) submerged at the time of the second fluid measurement, then subtract the volume of rod submerged from the difference in the two fluid volumes.
You need the length of the rod to compute the weight. To do so, you can calculate the volume of the rod, which would be length*Pi*22 multiplied by the density of MS, which is 7.86 g/cm3, or simply 15.72(Pi)*length of the rod Mildsteel rod 40mm dia. = 9.85 kg per metre. I think that is what you asked.
If the diameter of the rod is increased but the oil flow remains the same, the retraction speed of the cylinder rod will decrease. This is because a larger diameter rod requires more volume of oil to fill, resulting in slower movement when the same amount of oil is flowing through.
You look up the density of steel, then calculate the volume of the rod, then multiply the density by the volume to find the mass of the rod. To find the weight of the rod, you multiply it's mass by gravataional acceleration.The rod has a cross sectional area of Pi x (0.008 / 2)2 m2Volume of the rod = 1 x 5.027x10-5Steel has a density of approx. 7850 kg/m3.Mass = Density x VolumeMass = 7850 x 5.027x10-5Mass = 0.395 kgWeight = 0.398 x 9.81Weight = 3.871 Newtons
The weight of a steel rod can be calculated using the formula: weight = volume × density. The volume of a cylinder is given by the formula ( V = \pi r^2 h ), where ( r ) is the radius and ( h ) is the height. For an 8-foot long rod with a 3-inch diameter, the radius is 1.5 inches (0.125 feet). Using the density of steel, which is approximately 490 pounds per cubic foot, the rod weighs about 24.5 pounds.