What is the wavelength of an electromagnetic wave that has a frequency of 7.80x1014 Hz in a vacuum?

Answer 1

5 x 1018 kilometers

Answer 2

The wavelength of an electromagnetic wave can be calculated using the formula (\lambda = \frac{c}{f}), where (c) is the speed of light in a vacuum ((3.00 \times 10^8) m/s) and (f) is the frequency of the wave. Plugging in the values, we get (\lambda = \frac{3.00 \times 10^8 , \text{m/s}}{7.80 \times 10^{14} , \text{Hz}} \approx 3.85 \times 10^{-7} , \text{m}). Hence, the wavelength of an electromagnetic wave with a frequency of (7.80 \times 10^{14}) Hz in a vacuum is (3.85 \times 10^{-7}) meters.

Answer 3

If we use (3 x 108 m/s) for the speed of light, then the wavelength is (3 x 108) / (1 x 1015) = 3 x 10-7 meter = 300 nanometers

Answer 4

Wavelength = speed/frequency = 300 million meters per second/1 per second = 300 million meters.

Answer 5

Wavelength = speed/frequency = 299,792,458/5 x 1012 = 0.00006 meter = 0.06 millimeter

Answer 6

You need to divide the speed of light by the frequency (and do some unit conversion).

Answer 7

467nm (apex) or to be more precise: 4.66966445e-7 .

Answer 8

The answer is 5.0*1014 Hertz.

Answer 9

The wavelength is 1,9986.10e-8 cm.