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Volume of a cylinder is pi*r^2*h. That gives us pi*.003^2*1 = 28.274 * 10^-6 m^3.

We know the density of steel is 7850 kg/m^3, so simply multiplying the two numbers together gives:

.222 kg or 221.95 grams

Technically, the way the question is worded, .2 kg or 200 grams is as accurate as we can get, because the question only gives one significant figure.

Volume of a cylinder = [π x Ø2] x Height

4

Diameter Ø = 6 mm / 0.006 meter

Height = 1000 mm / 1 meter

Volume of a cylinder = [π x 0.0062] x 1= 0.000028274

4

Density of steel = 7850 kg/m3

Weight of 1 meter steel rod = 0.000028274 x 7850 = 0.221 kg

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13y ago
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13y ago

Mild steel has a density of 7.85 g/cm3

Volume of steel rod with diameter of 16mm and a length of 1m:

Volume = Pi x 0.82 x 100

Volume = 201 cm3

Mass = 201 x 7.85

Mass = 1577.85 g

Weight = 1.57785 x 9.82

Weight = 15.5 N

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12y ago

It's 1.579.

To compute for bar weight per meter:

d*d/162

or d*d*0.00617

where d = bar diameter

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14y ago

per metre in 50mm dia weight is 15.43 Kg/m

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12y ago

(.05+.05)*.006*7850= 4.71 KG

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12y ago

.230

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11y ago

wat

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12y ago

0.3655

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11y ago

8.2

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Q: What is the weight of 50x50x6 mm mild steel angle per meter length?
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