What is the weight of 50x50x6 mm mild steel angle per meter length?

Answer 1

Volume of a cylinder is pi*r^2*h. That gives us pi*.003^2*1 = 28.274 * 10^-6 m^3.

We know the density of steel is 7850 kg/m^3, so simply multiplying the two numbers together gives:

.222 kg or 221.95 grams

Technically, the way the question is worded, .2 kg or 200 grams is as accurate as we can get, because the question only gives one significant figure.

Volume of a cylinder = [π x Ø2] x Height

4

Diameter Ø = 6 mm / 0.006 meter

Height = 1000 mm / 1 meter

Volume of a cylinder = [π x 0.0062] x 1= 0.000028274

4

Density of steel = 7850 kg/m3

Weight of 1 meter steel rod = 0.000028274 x 7850 = 0.221 kg

Answer 2

The weight of a 50x50x6 mm mild steel angle per meter length can be calculated using the formula:

Weight = (Width x Thickness x 0.00785) in kg/m Weight = (50 mm x 6 mm x 0.00785) = 2.355 kg/m

Therefore, the weight of a 50x50x6 mm mild steel angle per meter length is approximately 2.355 kg.

Answer 3

Mild steel has a density of 7.85 g/cm3

Volume of steel rod with diameter of 16mm and a length of 1m:

Volume = Pi x 0.82 x 100

Volume = 201 cm3

Mass = 201 x 7.85

Mass = 1577.85 g

Weight = 1.57785 x 9.82

Weight = 15.5 N

Answer 4

It's 1.579.

To compute for bar weight per meter:

d*d/162

or d*d*0.00617

where d = bar diameter

Answer 5

per metre in 50mm dia weight is 15.43 Kg/m

Answer 6

(.05+.05)*.006*7850= 4.71 KG

Answer 7

.230

Answer 8

wat

Answer 9

0.3655

Answer 10

8.2