answersLogoWhite

0


Best Answer

Hello .

I checked this out to day with cartridges loaded in cases from one of these very useable Fenchmade sets .

I used a modified 200gn bullet, designed for use in muzzleloading revolvers .

They hit way too high( about 3-4 feet at 20 paces ), because of heavy bullet and rather slow velocity, cronographed at 165 meters/sec .

Not fast, but with a case not being long enough to take more than 14gn of 3F blackpowder , one can not expect velocities higher than this .

I will try to load with round balls next timel, and i expect these to go a bit faster .

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What muzzle velocity and bullet mass might a 12mm short pin-fire round have?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

If you shoot a gun up what is the velocity of the bullet coming down?

The velocity of a bullet coming down from altitude is the terminal velocity of the bullet fired. Since not all bullets are equal in mass, it would depend on the grain (weight) of the bullet fired, the caliber of the bullet, and the charge behind the bullet (which would determine the highest possible altitude it could reach). To determine the terminal velocity of any bullet, you must first know these variables and plug in those variables to the equation below: That is, * Vt = terminal velocity * m= mass of the bullet * g = gravitational acceleration * Cd = drag coefficient (wind resistance applied to the bullet as it falls) * ? = denisty of the medium through which the bullet is falling (the atmosphere) * A = projected area of the bullet (which can get complicated due to the shape of the ball). Essentially, the following is true: any bullet fired straight upward is not only potentially but very likely as deadly to anyone it might strike when it lands as if that same bullet were fired directly at that person.


Can an air soft gun pierce the skin of a cat?

no..it cannot...depends on the velocity of the bullet...if u hit it on the head then the cat might die...


What speed does a bullet return to earth?

If the bullet were shot perfectly vertically in a vacuum, it would reach its maximum altitude, then fall at a velocity of 32 ft/sec/sec. The terminal velocity would depend upon the altitude reached by the bullet, which in turn depends upon the caliber and load of bullet shot.


What is termanial velocity?

It might be an incorrect spelling of "terminal velocity".


When is the instantaneous velocity equal to avg velocity?

Mainly, when the velocity doesn't change. Also, in the case of varying velocity, the instantaneous velocity might, for a brief instant, be equal to the average velocity.


What might spell ceilotvy?

velocity


Give a short example of equal and opposite pairs?

Perhaps forces.When you fire a gun, you have an explosion of gunpowder that ejects the bullet forward at a high velocity. The gun kicks back in an opposite direction from the firing with a force equal to that which expelled the bullet, but in the opposite direction.Another example might be ice skating (without braking). If one person pushes the other backward... the pushing person will also be pushed backward with equal force. Acceleration/velocity, of course would be dependent on the relative weights.


When a bulltet is fired from a rifle it is the bullet which causes damage but nit recoiling gun answer you according to momentum or third law of motion?

I believe that you are asking if the bullet is what causes so much damage to something it strikes, then why doesn't the shooter suffer an equivalent amount of damage? The answer does have a lot to do with momentum. I think that there may be some confusion between the conservation of momentum, which is the essence of Newton's Third Law, and the definition of kinetic energy.The magnitude of the momentum of the bullet just as it leaves the barrel of a gun is equal to, but in the opposite direction of, the magnitude of the momentum of the gun plus any momentum imparted to the shooter's body.I apologize if you already know much of my answer, but I will show the equations for momentum and kinetic energy. Momentum is a vector because it has both direction and magnitude, and the equation for momentum is p = m•v, where p is momentum, m is the object's mass in kg, and v is the object's velocity in meters/sec. (The vector quantities are in bold. I'm using the units prescribed in the kms system.)The reason the bullet causes damage to whatever it strikes is due to the bullet's kinetic energy, which is defined by the equation Ek=1/2mv2, where m is the mass of the bullet in kg and v is the bullet's speed in meters/sec. The fact that the kinetic energy is proportional to the square of the velocity is of paramount importance. Just like momentum, energy is also conserved. Energy (or the combination of energy and mass in the cases of nuclear fission and nuclear fission) is never lost; it can only change forms. All the energy released from every bullet, bomb, and shell used in World War II, or any other war, is still present somewhere in the universe, although almost all of it is still present on the Earth in some form. Thus, the kinetic energy of a bullet fired from a gun is initially exactly equal to the kinetic energy imparted to the backward-moving gun, the gun's report, the flash of light from the muzzle, the heating of the gun's receiver, chamber, and barrel, the heating of the bullet and of whatever it hit, the frictional heating of the air through which the bullet passed, and the energy expended in damaging what the bullet struck.The reason the shooter of the gun is not severely damaged (although anyone who has ever fired a very powerful rifle such as a 375 H&H or a 460 Wetherby Magnum might disagree) is because the energy of the bullet is proportional to the square of the velocity. Because the mass of the gun is so much greater than the mass of the bullet, the rearward velocity of the gun is very much less than the velocity of the bullet such that the gun cannot cause significant damage to the shooter.


How far can a bullet from a 38 special pistol travel?

First, .38 Special handgun ammunition is typically fired from a revolver, which is not technically considered a pistol (from Wikipedia: "the term "pistol" refers to a handgun whose chamber is integral with the barrel, making pistols distinct from the other main type of handgun, the revolver, which has a revolving cylinder containing multiple chambers"). Second, .38 Special ammunition can be fired from a variety of firearms which alter the external ballistics and trajectory of a fired bullet (primarily barrel length and its effect on velocity). With these considerations, it is possible to generalize, as the most common .38 Special ammunition for target practice is probably the 158 grain round nose lead bullet being fired from a 4" barrel, which would exit the weapon's muzzle with a velocity of approximately 725 feet per second. This could in optimal conditions (warm, dry atmosphere, no wind, etc) result in a maximum range of about 1500 yards. Higher velocity (+P) ammunition might result in a maximum range of 2100+ yards. The terminal velocity would be approximately 350 feet per second in either case. Fired at shoulder level, horizontally (no elevation adjustment), the range is less than 200 yards.


Why a change in speed of the rover might not effect its velocity?

Either a change in speed or direction, or both, will affect its velocity. If there is a change in speed, then the rover's velocity has changed.


Can you shot a bullet with no gun?

Yes, a bullet can be shot with no gun. A bullet does not need a lot of speed to kill someone. Say someone threw a bullet to the ground, it might bounce back up and hit you, thus causing you to die or be injured


What does sswc bullet mean?

Might be Swaged Semi-Wad Cutter