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Why free fall acceleration can be regarded as a constant for objects falling within a few hundred miles of earths surface?
Free fall acceleration can be considered constant near Earth's surface because the gravitational force acting on an object is primarily determined by the mass of the Earth and the distance from its center. Within a few hundred miles of Earth's surface, these factors do not vary significantly, resulting in a consistent acceleration due to gravity of approximately 9.81 m/s^2. Therefore, objects in free fall experience a nearly constant acceleration regardless of their mass or size.
Explain why the gravitational acceleration of any object near the Earth is the same no matter what the mass of the object is?
Strictly speaking its not the same . This equation calculates the acceleration: acceleration = ( G * ( m1 + m2 ) ) / d2 where: G = newtons gravity constant m1 = earths mass (kg) m2 = objects mass (kg) d = distance between centres of gravity (metres) The earths mass is so large however, only a significantly large object mass would make a real difference to the acceleration.
What is the acceleration of an object in free fall at Earths surface?
The acceleration of an object in free fall at Earth's surface is approximately 9.8 m/s^2, which is due to the force of gravity. This acceleration is constant regardless of the mass of the object, as long as air resistance is negligible.
What is the importance of 9.81 in accelaration due to gravity?
9.81 is the acceleration due to the force of gravity experienced by bodies on or about the surface of the earth (nominally at sea level) the units are meters per second / per second, that is to say a stone dropped from a height will gain 9.81 m/s velocity for every second it falls (is in freefall) however , if you move from the earths surface , this figure will diminish, an example being : if you double your distance from the earths centre you will experience 1/4 of the acceleration (or force) you experienced at the surface
Why the acceleration due to gravity is 9.8 meter per second and velocity is changed?
gravity is force of attraction that exists between masses , the earth being one (large ) mass , and you , another. Just by standing on the earth the soles of your feet will register the force of attraction between you, although you can overcome the entire earths gravity by(for instance) climbing some stairs. Although the earths gravity diminishes the further you get away from it, you have to travel a good distance away before you notice the difference, so in practical terms the earths gravity remains constant and about the earths surface will produce an acceleration towards its centre of about 9.8((m/s)/s), that is to say if you drop a stone from a tower its velocity increase will be 9.8m/s over each one second interval, for example: time from drop(s) velocity(m/s) 0 ----------------------0 1 ----------------------9.8 2 ---------------------19.6 3 ---------------------29.4 see also equation : force = mass * acceleration (issac newton) so essentially if you apply a constant force (in this case, gravity ) to a mass (stone ), it will gain speed (accelerate) uniformly
What occurs when the objects free falls near earths surfaces?
Constant acceleration
Why free fall acceleration can be regarded as a constant for objects falling within a few hundred miles of earths surface?
Free fall acceleration can be considered constant near Earth's surface because the gravitational force acting on an object is primarily determined by the mass of the Earth and the distance from its center. Within a few hundred miles of Earth's surface, these factors do not vary significantly, resulting in a consistent acceleration due to gravity of approximately 9.81 m/s^2. Therefore, objects in free fall experience a nearly constant acceleration regardless of their mass or size.
What is the gravitational force on any object near the earths surface?
Force (newtons) = mass (kg) * acceleration (m/s/s) > Acceleration at earths surface radius = 9.82 m/s/s
What is The constant recycling of water from the earths surface?
the water cycle
Explain why the gravitational acceleration of any object near the Earth is the same no matter what the mass of the object is?
Strictly speaking its not the same . This equation calculates the acceleration: acceleration = ( G * ( m1 + m2 ) ) / d2 where: G = newtons gravity constant m1 = earths mass (kg) m2 = objects mass (kg) d = distance between centres of gravity (metres) The earths mass is so large however, only a significantly large object mass would make a real difference to the acceleration.
What describes droplets that condense on objects at the earths surface?
Dew
What is the surface gravity on earth?
The force of gravity on the earth is 9.8 m/s^2
What is the acceleration of an object approaching the earths surface?
Because gravity is not uniform across the entire surface of the earth and the centripetal force varies noticeably with latitude, the acceleration varies from point to point on Earth. At different points on Earth, objects fall with an acceleration between 9.78 and 9.82 m/s2 depending on latitude, with a conventional standard value of exactly 9.80665 m/s2 (approx. 32.174 ft/s2).
What is the acceleration of an object in free fall at Earths surface?
The acceleration of an object in free fall at Earth's surface is approximately 9.8 m/s^2, which is due to the force of gravity. This acceleration is constant regardless of the mass of the object, as long as air resistance is negligible.
What is the moisture that coats objects close to the earths surface called?
dark ages
What is the importance of 9.81 in accelaration due to gravity?
9.81 is the acceleration due to the force of gravity experienced by bodies on or about the surface of the earth (nominally at sea level) the units are meters per second / per second, that is to say a stone dropped from a height will gain 9.81 m/s velocity for every second it falls (is in freefall) however , if you move from the earths surface , this figure will diminish, an example being : if you double your distance from the earths centre you will experience 1/4 of the acceleration (or force) you experienced at the surface
What is makemakes gravity compared to earths gravity?
The acceleration of gravity at its surface is currently estimated as 0.4 m/s2 .That's about 4% of the acceleration of gravity on the Earth's surface.
