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Can the resultant or two vectors of the same magnitude be equal to the magnitude of either of the vectors?
No, the resultant of two vectors of the same magnitude cannot be equal to the magnitude of either of the vectors. The magnitude of the resultant of two vectors is given by the formula: magnitude = √(A^2 + B^2 + 2ABcosθ), where A and B are the magnitudes of the vectors and θ is the angle between them.
What is the magnitude of the resultant vectors when the angle between them is 60 degrees?
What about the two vectors? Are they of same magnitude? If so then the resultant is got by getting the resolved components. Here we need adjacent components. F cos30 + F cos30 = 2 F cos 30 = ./3 F If forces of different magnitude then we use R = ./ (P^2 + Q^2 + 2 P Q cos 60)
What is the angle between unit vectors i plus j and j plus k?
The angle between two vectors can be found using the dot product formula: A · B = |A| |B| cos(theta). In this case, the dot product of the two given unit vectors is (1)(0) + (1)(1) + (0)(1) = 1. The magnitudes of the vectors are √2 and √2, therefore cos(theta) = 1 / (2)(2) = 1/4, giving theta = arccos(1/4) ≈ 75.5 degrees.
When displacement have the opposite derection what do you do to determine the magnitude?
Displacement is a vector quantity. Hence, while finding resultant vector we need to use vector algebra and the properties of vectors. If the 2 displacement vectore are in opposite directions,it means that the angle between them is 180degrees and hence we can directly subtract them.
What is the formula for calculating magnitude of resultant vector?
|v| = vx|v| = Sqrt(vx2 + vy2)|v| = Sqrt(vx2 + vy2 + vz2)
How angle between vectors affects the resultant?
The Law of Cosines shows the affect of the angle between vectors. R^2 = (A+B)(A +B)*= (AA* + BB* + 2ABcos(AB)) If the angle is less than 90 degrees the resultant squared R^2 is greater than the sum of the vectors squared. If the angle is 90 degrees the resultant squared is the sum of the vectors squared. If the angle is greater than 90 degrees, the resultant squared is less than the Sum of the vectors squared.
Can the resultant or two vectors of the same magnitude be equal to the magnitude of either of the vectors?
No, the resultant of two vectors of the same magnitude cannot be equal to the magnitude of either of the vectors. The magnitude of the resultant of two vectors is given by the formula: magnitude = √(A^2 + B^2 + 2ABcosθ), where A and B are the magnitudes of the vectors and θ is the angle between them.
If the resultant of two vectors each of magnitide f is twice of magnitude F then angle bw?
If the resultant of two vectors, each of magnitude ( f ), is twice the magnitude ( F ), then the angle ( \theta ) between the two vectors can be determined using the formula for the resultant of two vectors: [ R = \sqrt{f^2 + f^2 + 2f^2 \cos \theta} ] Given that ( R = 2F ), we set ( R = 2f ) (assuming ( F = f )). This leads to the equation ( 4f^2 = 2f^2(1 + \cos \theta) ). Solving for ( \theta ), we find that ( \cos \theta = 0 ), which means ( \theta = 90^\circ ). Thus, the angle between the vectors is ( 90^\circ ).
What is the magnitude of the resultant vectors when the angle between them is 60 degrees?
What about the two vectors? Are they of same magnitude? If so then the resultant is got by getting the resolved components. Here we need adjacent components. F cos30 + F cos30 = 2 F cos 30 = ./3 F If forces of different magnitude then we use R = ./ (P^2 + Q^2 + 2 P Q cos 60)
What is the angle between unit vectors i plus j and j plus k?
The angle between two vectors can be found using the dot product formula: A · B = |A| |B| cos(theta). In this case, the dot product of the two given unit vectors is (1)(0) + (1)(1) + (0)(1) = 1. The magnitudes of the vectors are √2 and √2, therefore cos(theta) = 1 / (2)(2) = 1/4, giving theta = arccos(1/4) ≈ 75.5 degrees.
What is the angle between 2 vectors when their sum is maximum?
180 degrees* * * * *The exact opposite!Maximum = 0 degrees, minimum = 180 degrees.
What is it when two vectors' dot product is one?
That fact alone doesn't tell you much about the original two vectors. It only says that (magnitude of vector-#1) times (magnitude of vector-#2) times (cosine of the angle between them) = 1. You still don't know the magnitude of either vector, or the angle between them.
The resultant between 2 vectors can be found by placing the vectors?
ma0!
How do you find the area of a parallelogram using 2 vectors?
Given two vectors a and b, the area of a parallelogram formed by these vectors is:a x b = a*b * sin(theta) where theta is the angle between a and b, and where x is the norm/length/magnitude of vector x.
Can the scaler product of two vectors be negetiv if the answer is yes provid a proof and given exampl?
Yes, for example the vectors <1, 0> and <-1, 0>. In general, if the angle between the two vectors is more than 90 degrees (or pi/2 radians), the scalar product is negative.
What is the angle between vector A and vector B for which modA plus B is equal to modA-B?
The condition ( | \mathbf{A} + \mathbf{B} | = | \mathbf{A} - \mathbf{B} | ) implies that the vectors are oriented such that their magnitudes are equal when added and subtracted. This occurs when the angle ( \theta ) between vectors ( \mathbf{A} ) and ( \mathbf{B} ) is ( 90^\circ ) (or ( \frac{\pi}{2} ) radians). Thus, the angle between vector ( \mathbf{A} ) and vector ( \mathbf{B} ) is ( 90^\circ ).
Can the sum of magnitudes of two vectors ever be equal to the magnitude of the sum of these two vectors?
Sure, if the two vectors point in the same direction.When we need the sum of magnitudes of two vectors we simply add the magnitudes, but to get the magnitude of the sum of these two vectors we need to add the vectors geometrically.Formula to find magnitude of the sum of these two vectors is sqrt[ |A|2 +|B|2 +2*|A|*|B|*cos(z) ] where |A| and |B| are magnitudes of two A and B vectors, and z is the angle between the two vectors.Clearly, magnitude of sum of two vectors is less than sum of magnitudes(|A| + |B|) for all cases except when cos(z)=1(for which it becomes = |A| + |B| ). Cos(z)=1 when z=0, i.e. the vectors are in the same direction(angle between them is 0).Also if we consider addition of two null vectors then their sum is zero in both ways of addition.So, we get two caseswhen the two vectors are in same direction, andwhen the two vectors are null vectors.In all other cases sum of magnitudes is greater than magnitude of the sum of two vectors.
