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What will be the acceleration of a skydiver when air resistance builds up to be half her weight?
Wiki User
∙ 13y ago
5 m/s^2 (or 4.9 m/s^2 if you want to be exact)
Since acceleration is zero when air resistance is equal to weight of object, and the most acceleration possible is 10 m/s^2 (or specifically, 9.8 m/s^2), then when air resistance is half of her weight, acceleration is also half, meaning 5m/s^2.
Wiki User
∙ 13y ago
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What is a skydivers velocity after 2 seconds?
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.
Why won't a skydiver's speed continue to increase until his or her parachute opens?
Once a skydiver jumps off the plane, they will begin picking up speed. However, as the speed of the skydiver increases, the amount of air resistance acting upon them will also increase. The skydiver will continue to accelerate while his or her weight is greater than the air resistance. When the force of the air resistance becomes equal to the weight of the skydiver, the skydiver will stop accelerating and will continue falling at a constant speed, this is known as the terminal velocity. While travelling at terminal velocity, the skydiver will be able to adjust his or her body position in a way that will increase or decrease the air resistance and allow the diver to alter their speed. Releasing his or her parachute will drastically increase the amount of air resistance and therefore slow their descent significantly.
What is the acceleration of two falling sky divers mass 112.0 kg including parachute when the upward force of air resistance is equal to one-fourth of their weight?
If air resistance is 1/4 of the falling object's weight, then the net force on it ...(gravity + air resistance) ... is 3/4 of its weight downward. Its acceleration thenmust be 3/4 of the acceleration of gravity, or 7.36 meters (24.1 feet) per second2.The mass of the object, or how many of them there are, makes no difference.You took care of that when you said that the air resistance is 1/4 of its weight.
If you removed air resistance would objects fall with constant acceleration?
Yes. Neglecting the effects of air resistance, all objects near the surface of the earth fall with the same constant acceleration, regardless of their mass/weight.
How does terminal velocity affect acceleration?
The terminal velocity of an object moving through a fluid under the force of gravity (let's assume the fluid is air for sake of discussion) occurs at the speed where the drag force of the air on the object becomes equal to the weight of the object. At this point the object has stopped accelerating and is in uniform motion (constant speed).For example, a skydiver jumping out of a plane will accelerate towards the Earth. At first the skydiver is accelerating at 9.8 m/s2, the gravitational acceleration of the Earth. But as he accelerates to higher speed, drag force becomes greater and the rate of acceleration slows. Drag force is proportional to the square of the speed, by the way. Eventually the skydiver will reach a speed (around 120 mph depending on the orientation of the skydiver's body) where the drag force is equal to his weight. That will be his terminal velocity.
What is a skydivers velocity after 2 seconds?
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.
When a skydiver has reached terminal speed what is the air resistance equal to?
Fnet=Fgravity-Fair resistance At terminal velocity Force Net = 0 during this time Fgravity = Fair resistance if you weight is 85kg Fgravity = Mass x G = 85x 9.8 = 833N your at terminal velocity when Air resistance is equal to 833 Newtons
Weight equals mass X acceleration of free-fall?
No, because acceleration of free fall is gravitational acceleration minus air resistance. Weight does not involve air resistance.
Why won't a skydiver's speed continue to increase until his or her parachute opens?
Once a skydiver jumps off the plane, they will begin picking up speed. However, as the speed of the skydiver increases, the amount of air resistance acting upon them will also increase. The skydiver will continue to accelerate while his or her weight is greater than the air resistance. When the force of the air resistance becomes equal to the weight of the skydiver, the skydiver will stop accelerating and will continue falling at a constant speed, this is known as the terminal velocity. While travelling at terminal velocity, the skydiver will be able to adjust his or her body position in a way that will increase or decrease the air resistance and allow the diver to alter their speed. Releasing his or her parachute will drastically increase the amount of air resistance and therefore slow their descent significantly.
What will be the acceleration of a skydiver when air resistance is one tenth the weight of the skydiver?
Terminal airspeed for a skydiver is approximately 120mph (oriented on belly). Mass of the skydiver affects the speed ! So heavier generally falls faster. (drop a ping pong ball versus a golfball) So, the weight of the skydiver will not affect the air resistance. His clothing will affect it, and his body position. Lastly, air pressure changes with altitude, so the density of the air is less as you go higher. So, exit altitude will also be a factor, as the air pressure will change the air resistance due to density. Bet you're sorry you asked. As a skydiving instructor, if I weighed 1/10 my weight, i would expect to fall really slow. something ridiculous, like 30mph. If you made air resistance 1/10th we would get going quite fast. 200-250mph? Col Joe Kittenger jumped form 103,000feet from a balloon. He experienced an almost frictionless descent for a bit, which led people to believe to break the sound barrier.
Are people weightless in the air?
No. Things are only weightless in the absence of a gravitational field or in constant acceleration (Inertial weight or mass) (Ask any skydiver.)
Will the weight of the skydiver affect the fall time?
The weight of the sky diver has minimal effect on freefall time. Body position and amount of surface area exposed for wind resistance to affect are the two largest factors, and are interrelated to one another.
What is the acceleration of two falling sky divers mass 112.0 kg including parachute when the upward force of air resistance is equal to one-fourth of their weight?
If air resistance is 1/4 of the falling object's weight, then the net force on it ...(gravity + air resistance) ... is 3/4 of its weight downward. Its acceleration thenmust be 3/4 of the acceleration of gravity, or 7.36 meters (24.1 feet) per second2.The mass of the object, or how many of them there are, makes no difference.You took care of that when you said that the air resistance is 1/4 of its weight.
How much air resistance acts on a 500 N skydiver that falls at her terminal velocity?
500 N is pressumably the weight, due to gravity. "Terminal velocity" means that the forces are in balance; the total force acting on the skydiver are zero. This is only possible if there is a 500 N force due to friction, to counteract the weight.
If you removed air resistance would objects fall with constant acceleration?
Yes. Neglecting the effects of air resistance, all objects near the surface of the earth fall with the same constant acceleration, regardless of their mass/weight.
How does terminal velocity affect acceleration?
The terminal velocity of an object moving through a fluid under the force of gravity (let's assume the fluid is air for sake of discussion) occurs at the speed where the drag force of the air on the object becomes equal to the weight of the object. At this point the object has stopped accelerating and is in uniform motion (constant speed).For example, a skydiver jumping out of a plane will accelerate towards the Earth. At first the skydiver is accelerating at 9.8 m/s2, the gravitational acceleration of the Earth. But as he accelerates to higher speed, drag force becomes greater and the rate of acceleration slows. Drag force is proportional to the square of the speed, by the way. Eventually the skydiver will reach a speed (around 120 mph depending on the orientation of the skydiver's body) where the drag force is equal to his weight. That will be his terminal velocity.
How does the weight of a falling body compare with the air resistance it encounters before it reaches terminal velocity?
The weight exceeds the force of air resistance, but as the speed increases the air resistance increases, so the net force (weight - air resistance) falls. When the difference becomes zero the acceleration ceases and you have terminal velocity.
