Since the distance from the Earth's center will be doubled, the force or weight will be reduced by a factor of 4.
The weight of a body when raised above the Earth to a height equal to its radius will decrease. This is because the force of gravity acting on the body decreases with distance from the center of the Earth. The weight of the body can be calculated using the formula: ( W = mg ), where ( W ) is the weight, ( m ) is the mass of the body, and ( g ) is the acceleration due to gravity.
weight on jupiter=((mass of jupiter)*(Radius of earth)2/(mass of earth)*(Radius of jupiter)2)*weight on earth
The force exerted by the weight of the air above is called atmospheric pressure. It is the pressure exerted on Earth's surface by the weight of the air in the atmosphere above it.
Yes, pressure is the force per unit area exerted by the weight of the atmosphere above a point on the Earth's surface. This pressure decreases with increasing altitude due to the decreasing weight of the air column above.
The weight of an object becomes half at a height where the gravitational force is half of the force on Earth, about 3,578 km above Earth's surface. At this height, the object and Earth are attracted with equal and opposite force.
The weight of a body when raised above the Earth to a height equal to its radius will decrease. This is because the force of gravity acting on the body decreases with distance from the center of the Earth. The weight of the body can be calculated using the formula: ( W = mg ), where ( W ) is the weight, ( m ) is the mass of the body, and ( g ) is the acceleration due to gravity.
10bls
The radius of Earth in kilometers is 6400 km.The earth is big in 6400 km in radius above its surface.
Yes, in a way. If the radius of the Earth decreased but it's mass stayed the same, then the forces "pulling" on you (weight) would increase and you would be heavier. If the radius of the Earth increased and the mass stayed the same, then you would be lighter. You would actually weigh less on the top of Mount Everest than on the beach of Honolulu. BTW: This is not a good idea for a weight loss program.
weight on jupiter=((mass of jupiter)*(Radius of earth)2/(mass of earth)*(Radius of jupiter)2)*weight on earth
The strength of the gravitational forces between two masses decreases as the square of the distance between their centers. The average Earth radius is 6,371 km. 150,000 km is 23.54 times the Earth's radius. So the acceleration of gravity, and hence the weight of an object, is (23.54)^-2 = 0.0018 of its value on the Earth's surface.
At an altitude above the ground which is equal to the radius of the earth.
the same
The force exerted by the weight of the air above is called atmospheric pressure. It is the pressure exerted on Earth's surface by the weight of the air in the atmosphere above it.
Venus has a radius of about 6,052 kilometers, which is about 95% of Earth's radius.
The mass of an object at any point will remain the same( unless its velocity approaches that of light, of course )So, for the weight to reduce to half its value, the acceleration due to gravity has to reduce to half its value on earth. now, the relation between acceleration due to gravity and distance from the center of the earth is given by g = 1/R2 where R is the radius of the earth which is 6400 kms (approx) let 'h' be the height at which the weight of the rocket will be half its initial value. so, gh / g = R2 / (R+h)2 but gh = g/ 2 substituting it in the above expression yields h=2649.6 kms (approx) so, at this height, the weight of the rocket will be half its initial weight.
The gravitational force between you and the Earth (your "weight") depends on both of the masses . . . the Earth's and yours . . . and on the distance between your centers . . . the Earth's and yours. As soon as you rise from the Earth's surface, your weight begins to decrease, because the distance between you and the Earth's center is increasing. The direct answer to your question is: The gravitational force between you and the Earth begins to diminish at the Earth's surface. The higher off the surface you go, the weaker the gravitational force becomes. In a passenger jet, let's say, cruising at 37,000 ft above the surface, your weight is about 0.46% less than it is when you're on the ground. ========================= [Earth radius/Earth radius plus 37,000 ft]2 = [3,950 miles/3,957 miles]2 = 0.99647