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It doubles.

cw: IT Depends! Example: If you have a first mass moving frictionlessly and you double the first mass by adding a second mass that isn't moving, then the new momentum will stay the same (!) and the kinetic energy is reduced by half. (m1+m2)(v/2) = 2m1(v/2)=m1(v) --> same momentum vs (1/2)m1(V*V) vs. (1/2) (2m1) (v/2)(v/2) = (1/2) m1 (v)(v/2) --> half the kinetic energy, (v/;2)

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When the speed of body is doubled kinetic energy becomes?

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