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What will happen to the resistance of a wire if it is stretched to increase its length by 2 times?
Actually resistance is directly proportional to the length provided area remains constant. But as we stretch the wire only its volume would remain constant. So its area is to be decreased as length increases. V = pi r^2 * L
Now we have R = K * L / pi r^2
Multiplying numerator and denominator by L we get R = K/V * L^2
So resistance is found to be proportional to square of length
Hence as length gets increased by 2 times, its resistance value would increase by 4 times.
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What will happen to the resistance of a wire if it is stretched to increase its length by 4 times?
Assume that the increase in length is achieved by uniform reduction in the cross-sectional area of the wire. Then an increase in length by 4 times will result in the cross sectional area being reduced to a fifth of it original value. This will increase the resistance to five times its previous value.
If both the diameter of wire and its length were quadrupled what will happen to its resistance?
If both the diameter and length of a wire are quadrupled, the resistance of the wire will increase by a factor of 16. This is because resistance is directly proportional to the length of the wire and inversely proportional to the cross-sectional area of the wire, which is determined by the diameter. By quadrupling both, the resistance will increase by 4^2 = 16 times.
If a wire of resistivity is stretched to thrice its initial length what will be its new resistivity?
The new resistivity of the wire will remain the same, as resistivity is a material property and is independent of the dimensions of the wire. The resistance of the wire will increase because of the increase in length.
How does length affect the resistance?
Length directly affects resistance in a conductor. The longer the conductor, the higher the resistance due to increased collisions between electrons and atoms, leading to more energy loss. This is described by the formula R = ρ x (L/A), where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.
A wire with a resistance R is lengthend to 1.25 times its original length by being pulled through a small holefind the resistance of the wire after it has been stretched?
The resistance of a material is defined as: R = r * l / A where r (actually it is the Greek alphabet rho) is the specific resistance and is independent of shape, structure, etc, but is specific to the material only; l is the length and A is the area of cross section. Let R1 = r * (l1/A1) and after stretching it becomes R2 = r * (l2/A2) R2/R1 = (l2/l1)*(A1/A2) -------------------------- equation 1 If the wire has been stretched with no loss of material, the volume remains the same. Hence, l1A1 = l2A2 which gives A1 = A2*(l2/l1). given that (l2/l1) is 1.25, we get A1/A2 = 1.25 Using this value in equation 1, we get R2/R1 = 1.25 * 1.25 = 1.5625 Hence, the resistance of the wire increases by a factor of 1.5625. - Karthik
What will happen to the resistance if the length of the conductor increase?
ERMM THE RESISTANCE INCREASES ) when longer
What will happen to the resistance of a wire if it is stretched to increase its length by 4 times?
Assume that the increase in length is achieved by uniform reduction in the cross-sectional area of the wire. Then an increase in length by 4 times will result in the cross sectional area being reduced to a fifth of it original value. This will increase the resistance to five times its previous value.
An electric heater is stretched to increase its length by 25 percent what is the increase in resistance?
The resistance of the electric heater will increase by approximately 56.25% (25% increase in length results in a 56.25% increase in resistance). This relationship is given by the formula: new resistance = (1 + 0.25)^2.
A piece of wire is stretched such that its length increases and its radius decreases the resistance of the wire will tend to?
A piece of wire stretched such that its length increases and its radius decreases will tend to have its resistance increase. The formula for this is: R = ρL/A where ρ = resistivity of the material composing the wire, L = length of the wire, and A = area of the conducting cross section of the wire. It can easily be seen that as area decreases resistance gets higher. In the case proposed the wire length is not reduced as it is stretched to reduce the area, this increases the resistivity as well.
If both the diameter of wire and its length were quadrupled what will happen to its resistance?
If both the diameter and length of a wire are quadrupled, the resistance of the wire will increase by a factor of 16. This is because resistance is directly proportional to the length of the wire and inversely proportional to the cross-sectional area of the wire, which is determined by the diameter. By quadrupling both, the resistance will increase by 4^2 = 16 times.
What happen to resistance if length is increased?
it increases
Suppose a wire of resistance R could be stretched uniformly until it was twice its original length. What would happen to its resistance?
Current tends to travel on the surface of the wire. As you decrease the cross-sectional area of a wire the resistance increases. That is why larger wires are rated for higher currents.
If a wire of resistivity is stretched to thrice its initial length what will be its new resistivity?
The new resistivity of the wire will remain the same, as resistivity is a material property and is independent of the dimensions of the wire. The resistance of the wire will increase because of the increase in length.
A wire of uniform cross section and length L has a resistance of 16ohm It is cut into four equal parts Each part is stretched uniformly to length L and all the four stretched parts are connected in?
When i will be a pro will help
How does length affect the resistance?
Length directly affects resistance in a conductor. The longer the conductor, the higher the resistance due to increased collisions between electrons and atoms, leading to more energy loss. This is described by the formula R = ρ x (L/A), where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.
Three ways which resistance of a wire can be increased?
You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).
A wire with a resistance R is lengthend to 1.25 times its original length by being pulled through a small holefind the resistance of the wire after it has been stretched?
The resistance of a material is defined as: R = r * l / A where r (actually it is the Greek alphabet rho) is the specific resistance and is independent of shape, structure, etc, but is specific to the material only; l is the length and A is the area of cross section. Let R1 = r * (l1/A1) and after stretching it becomes R2 = r * (l2/A2) R2/R1 = (l2/l1)*(A1/A2) -------------------------- equation 1 If the wire has been stretched with no loss of material, the volume remains the same. Hence, l1A1 = l2A2 which gives A1 = A2*(l2/l1). given that (l2/l1) is 1.25, we get A1/A2 = 1.25 Using this value in equation 1, we get R2/R1 = 1.25 * 1.25 = 1.5625 Hence, the resistance of the wire increases by a factor of 1.5625. - Karthik
