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What happened to the wavelength and frequency when you increased the rate at which the spring toy moved left and right?
When you increase the rate at which the spring toy moves left and right, the frequency of the wave it generates also increases because each oscillation completes in a shorter time. This results in a shorter wavelength since the distance between successive crests (or troughs) of the wave decreases as the frequency increases.
Explain the effects on frequency wavelength and energy as you move across the spectrum?
As you move from left to right across the electromagnetic spectrum, the frequency increases, the wavelength decreases, and the energy of the electromagnetic waves increases. This means that on the left side, you have low-frequency, long-wavelength, low-energy waves like radio waves, while on the right side, you have high-frequency, short-wavelength, high-energy waves like gamma rays.
Can you change the frequency of em wave?
Once the wave has left the source that generated it, the frequency can't be changed.If you happen to be moving toward or away from the source at a high enoughspeed, then the frequency of the radiation may appear to you to be changed.But it's not.
Is ultraviolet the shortest wavelength?
No. If the shortest wavelength is on the left end of the spectrum, the shortest wavelength is microwaves. if the shortest wavelength is on the right end of the spectrum, the shortest wavelength is gamma rays. I think it is microwaves because micro means small.
The energy of a photon is related to its?
The energy of a photon is related to its frequency or wavelength through the equation E=hf, where E is energy, h is Planck's constant, and f is frequency. Alternatively, you can use the equation E=hc/λ, where λ is the wavelength and c is the speed of light.
What happened to the wavelength and frequency when you increased the rate at which the spring toy moved left and right?
When you increase the rate at which the spring toy moves left and right, the frequency of the wave it generates also increases because each oscillation completes in a shorter time. This results in a shorter wavelength since the distance between successive crests (or troughs) of the wave decreases as the frequency increases.
Explain the effects on frequency wavelength and energy as you move across the spectrum?
As you move from left to right across the electromagnetic spectrum, the frequency increases, the wavelength decreases, and the energy of the electromagnetic waves increases. This means that on the left side, you have low-frequency, long-wavelength, low-energy waves like radio waves, while on the right side, you have high-frequency, short-wavelength, high-energy waves like gamma rays.
Can you change the frequency of em wave?
Once the wave has left the source that generated it, the frequency can't be changed.If you happen to be moving toward or away from the source at a high enoughspeed, then the frequency of the radiation may appear to you to be changed.But it's not.
When a gas or liquid is heated then its mass is?
The mass remain unchanged.
Is ultraviolet the shortest wavelength?
No. If the shortest wavelength is on the left end of the spectrum, the shortest wavelength is microwaves. if the shortest wavelength is on the right end of the spectrum, the shortest wavelength is gamma rays. I think it is microwaves because micro means small.
The energy of a photon is related to its?
The energy of a photon is related to its frequency or wavelength through the equation E=hf, where E is energy, h is Planck's constant, and f is frequency. Alternatively, you can use the equation E=hc/λ, where λ is the wavelength and c is the speed of light.
How do you find the wavelength from wave speed?
draw a triangle and make 3 areas in the triangle. on the top is S or Speed. on the bottom left is F or Frequency. and on the bottom right is a bckwards/upside down Y for Wavelength. then S divided by For Y. and F times Y. will get you wavelength and what you need. draw what i just said.
As you go from left to right across the spectrum what happens to the frequency and energy of the waves?
As you go farther right down the spectrum (radio waves, microwaves, infrared waves, visible light, ultraviolet light, x-rays, and gamma rays), the waves' wavelengths decrease as their frequencies decrease. For example, x-rays have a shorter wavelength and higher frequency than ultraviolet light. Radio waves on the left end have the longest wavelength and shortest frequency, while gamma rays on the right end have the shortest wavelength and highest frequency.
The string of a piano that produces the note middle C vibrates with a frequency of 262 Hz. If the sound waves produced by this string have a wavelength in air of 1.30 m what is the sound waves?
Question is to be corrected as to find the velocity of the sound waves Formula for velocity of the wave = frequency x wavelength Given frequency = 262 Hz and wavelength = 1.3 m So velocity = 262 x 1.3 = 340.6 m/s
In classical physics how does an atomic oscillator behave when heated in terms of energy emissions?
The oscillator starts at relatively low frequency and emits electromagnetic radiation of relatively low frequency (or long wavelength) and low intensity. As the heating continues, the frequency of oscillation also increases as does the frequency of the emitted radiation and the intensity of the radiation. A graph of intensity vs. wavelength would start high on the left (at short wavelengths) and fall off to the right exponentially to low intensity at long wavelengths. This graph would be at odds with the experimentally established graph of intensity vs. wavelength(which shows low intensity at short wavelengths) because the classical assumption that frequency of oscillation can increase continuously as the oscillators are heated is not correct. Frequency of oscillation can increase only in integral multiples of the fundamenal frequency.
What is a contolled variable?
A controlled variable is a variable left unchanged in an experiment
When After a congruence transformation the area of a triangle would be?
It would be left unchanged.
