The stopping distance can be calculated using the equation: stopping distance = (initial velocity^2) / (2 * deceleration). The deceleration can be calculated using the formula: deceleration = force / mass. Plugging in the values and calculating will give you the stopping distance.
3000 Kg = 3 tonnes.
No, 300g (grams) is smaller than 3000kg (kilograms) because there are 1000 grams in 1 kilogram.
1 pound = 0.452 kilo so 3000 pounds equals 1356 kilos
change in velocity =accleration. Suppose a car is moving at 30km\hr at 6:30 am and then the velocity of the car is noted to be 100km\hr at 7:30am.thus the change in velocity of the car =100-70=30 km\hr over a time of (6:30am-7:30am) 1hr.Thus the accleration of the car=30km/hr*hr.Force however is the product of the mass of the car and the accleration by which the car is travelling.Let the mass of the car be 100kg.Thus the force =100*30=3000kg*km/hr*hr.
The net force required to accelerate the car at a rate of 2 m/s^2 is 6000 N. This is calculated using Newton's second law, F = ma, where F is the force, m is the mass of the car (3000 kg), and a is the acceleration (2 m/s^2). So, F = 3000 kg * 2 m/s^2 = 6000 N.
The stopping distance for a 3000kg car if 3000 N of force is applied when the car is traveling 10 ms is 50 meter. This is based on Newton's second law of force.
50m
3000 Kg = 3 tonnes.
60000
No, 300g (grams) is smaller than 3000kg (kilograms) because there are 1000 grams in 1 kilogram.
3 tonnes
Force = mass X acceleration, F=ma=3000kg X 6m/s2=18000kgm/s2=18 kilonewtons
3000kg = 6,613lb 13.9oz
3000kg = 6,613lb 13.9oz
3000kg. kilograms is a measurement for mass.
round about 3000kg
3000kg is 3 tonnes.