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If the velocity-time graph is a straight line parallel to the time axis, it means the velocity is constant. The acceleration would be 0 because there is no change in velocity over time.

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1y ago

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What does the graph of acceleration vs. time look for something going constant velocity?

a horizontal line


Is a horizontal line on the velocity vs. time graph indicates a constant positive acceleration ture or false?

False. A horizontal line on a velocity vs. time graph indicates constant velocity, not constant acceleration. Positive acceleration would be represented by a diagonal line sloping upwards on a velocity vs. time graph.


What is the value of acceleration if v-t graph is a straight line parallel to the time axis?

The problem is that a so-called "velocity-time" graph is really a "speed-time" graph.A complete description of "velocity" at any point in time includes speed and direction,but the graph can only show speed, that is, the magnitudeof velocity, vs. time, butit can't show the direction of the motion. If the direction changes with time, thenthat constitutes acceleration, but we can't discern it from the graph.If the "v-t" graph is a straight line parallel to the time axis, then we know the speed,and therefore the magnitude of velocity, is not changing. If we also know from someother source that the motion is in a straight line, then we may say that the accelerationis zero. But if we have no other information in addition to the graph, we can't reach afull conclusion regarding the acceleration.


What does constant acceleration of a velocity time graph look like?

A constant acceleration on a velocity-time graph would appear as a straight line with a non-zero slope. The slope of the line represents the acceleration, with a steeper slope indicating a greater acceleration.


Velocity is the slope of the displacement vs time graph?

Velocity is NOT the slope of the acceleration vs. time graph. Velocity is the area under the acceleration vs. time graph. Velocity is the slope of a position vs. time graph, though. For you Calculus Junkies, v = the integral of acceleration with respect to time.

Related Questions

Does the horizontal line on the velocity vs time graph indicate a constant and positive acceleration?

Ahorizontal line on a velocity vs time graph does not indicate any acceleration because there is no slope. Speed remains constant.


Is The slope on a position-time graph is representative of the acceleration of the object?

No. Slope of position/time graph is speed, or magnitude of velocity.Slope of speed/time graph is magnitude of acceleration.


What does the graph of acceleration vs. time look for something going constant velocity?

a horizontal line


Is a horizontal line on the velocity vs. time graph indicates a constant positive acceleration ture or false?

False. A horizontal line on a velocity vs. time graph indicates constant velocity, not constant acceleration. Positive acceleration would be represented by a diagonal line sloping upwards on a velocity vs. time graph.


What is the value of acceleration if v-t graph is a straight line parallel to the time axis?

The problem is that a so-called "velocity-time" graph is really a "speed-time" graph.A complete description of "velocity" at any point in time includes speed and direction,but the graph can only show speed, that is, the magnitudeof velocity, vs. time, butit can't show the direction of the motion. If the direction changes with time, thenthat constitutes acceleration, but we can't discern it from the graph.If the "v-t" graph is a straight line parallel to the time axis, then we know the speed,and therefore the magnitude of velocity, is not changing. If we also know from someother source that the motion is in a straight line, then we may say that the accelerationis zero. But if we have no other information in addition to the graph, we can't reach afull conclusion regarding the acceleration.


What does constant acceleration of a velocity time graph look like?

A constant acceleration on a velocity-time graph would appear as a straight line with a non-zero slope. The slope of the line represents the acceleration, with a steeper slope indicating a greater acceleration.


Velocity is the slope of the displacement vs time graph?

Velocity is NOT the slope of the acceleration vs. time graph. Velocity is the area under the acceleration vs. time graph. Velocity is the slope of a position vs. time graph, though. For you Calculus Junkies, v = the integral of acceleration with respect to time.


What would the graph look like on a position verse time plot with constant acceleration?

If the constant acceleration is positive, the graph would be an exponential (x2) graph. If there is constant acceleration, then velocity is always increasing, making the position change at an ever increasing rate.


Is it possible of a body to have its velocity and acceleration pointing in opposite direction plot a velocity-time graph if yes?

Yes, it is possible for a body's velocity and acceleration to be in opposite directions. This would result in the body's velocity decreasing over time while its acceleration remains negative. On a velocity-time graph, this situation would be represented by a curve that starts with a positive velocity and decreases over time.


How would one determine Acceleration from a V-t Graph?

Acceleration can be determined from a velocity-time graph by calculating the slope of the line on the graph. The steeper the slope, the greater the acceleration. If the graph is curved, acceleration can be calculated by finding the tangent to the curve at a specific point.


In the graph which region shows nonuniform positive acceleration?

A region with nonuniform positive acceleration on a velocity-time graph would appear as a curved or non-linear section where the velocity is increasing at a variable rate.


What does the slope of a velocity time graph represent?

Slope just means "rate of change", so you can rephrase your question as "what do you call the rate of change in velocity over time?". When you look at it this way it's more apparent that the answer is acceleration. Hope this helps.