What would be the capacitance of a capacitor if an electric current of 6.8 uA is used to charge parallel plate capacitor at a rate of 8.4volts per second?

Answer 1

1 coulomb = 1A x 1s

1 coulomb = 1F x 1V

therefore 1F x 1V = 1A x 1s

1F = 1A / (1V/s)

F = 6.8uA / 8.4V/s

F = 0.8095 uF

Answer 2

The formula for capacitance is C = Q/V, where C is capacitance, Q is charge, and V is voltage. Given that the current is 6.8 uA and the voltage rate is 8.4 V/s, the charge rate can be calculated as Q = I * t, where I is current and t is time. Plugging in these values, we can find the capacitance.