An emitter of blue light shining on/through a red filter.
The red filter appears red because it block all light except red. So trying to shine blue through it should attenuate the blue heavily. Only red can pass through the red filter easily.
If you put a blue filter in the path of a ray of light, the filter would absorb all colors of light except for blue. This would result in the light passing through the filter appearing blue in color.
A "beam" or "ray" of light would best describe the light that shines from a flashlight.
If a red light is shined through a blue filter, the blue filter would absorb the red light since it is not in the transmitted light spectrum. This would result in very little to no light passing through the blue filter, creating darkness or a very dim output depending on the intensity of the red light source.
If you place a blue filter in the path of light coming through a red filter, the blue filter will absorb or block the red light, potentially resulting in less intense light or a different color of light that is transmitted through. The combination of the two filters will likely produce a color that is a mix of the two original colors, such as purple or magenta.
It depends on what kind of filter, e.g. a blue filter absorbs everything except blue light, so only blue light comes out, which is why the filter looks blue, and is referred to as a "blue filter".
If you put a blue filter in the path of a ray of light, the filter would absorb all colors of light except for blue. This would result in the light passing through the filter appearing blue in color.
A "beam" or "ray" of light would best describe the light that shines from a flashlight.
If a red light is shined through a blue filter, the blue filter would absorb the red light since it is not in the transmitted light spectrum. This would result in very little to no light passing through the blue filter, creating darkness or a very dim output depending on the intensity of the red light source.
A red filter blocks every color except red from getting through, so you would see red.
black
If a pure red filter is placed in the path of the white light, only the red component of the light would pass through, resulting in a pattern on the screen showing only shades of red. The other colors of the spectrum that were originally present would be blocked by the filter.
If it has light, the flashlight is working.
If you place a blue filter in the path of light coming through a red filter, the blue filter will absorb or block the red light, potentially resulting in less intense light or a different color of light that is transmitted through. The combination of the two filters will likely produce a color that is a mix of the two original colors, such as purple or magenta.
It depends on what kind of filter, e.g. a blue filter absorbs everything except blue light, so only blue light comes out, which is why the filter looks blue, and is referred to as a "blue filter".
Obviously the excact same Red.
Only the green portion of the white light would pass through the green filter. The filter absorbs all colors except green, allowing only green light to pass through.
Using a blue filter for spectroscopy would selectively transmit blue wavelengths of light while blocking other wavelengths. This would result in the spectrograph only detecting and recording blue light emitted or absorbed by the sample being analyzed, leading to a limited spectral range in the data collected.