The power used, assuming Unity Power Factor (resistive load), is the product of resistance and the square of the current -- or 1210 Watts.
To find the current in the circuit, you can use the formula: Power = Current^2 * Resistance. Given the values, you can rearrange the formula to solve for current: Current = sqrt(Power / Resistance). Plugging in the values, you get Current = sqrt(2 / 30) which simplifies to approximately 0.27 amperes.
No, power is not directly proportional to resistance. The power dissipated in a circuit is given by P = I^2 * R, where I is the current flowing through the circuit and R is the resistance. This means that power is proportional to the square of the current but linearly proportional to resistance.
The formula for calculating current in a circuit when given the values of power and resistance is i p/a.
There is no particular reason why a motor should have a bigger resistance than a bulb. A motor's resistance must depend on what current it draws at the particular voltage it was designed to run on. Equally, a bulb's resistance must depend on what current it draws at the particular voltage it was designed to run on. A particular motor may have a higher resistance than one kind of bulb but that same motor may have a lower resistance than another kind of bulb.
The relationship between power (P), current (i), and resistance (r) in an electrical circuit is described by the formula P i2 r. This means that power is directly proportional to the square of the current and the resistance in the circuit.
Ohm's law: Voltage = Current times Resistance Solve: Resistance = Voltage divided by Current So, a device drawing 50ma with 150V has a resistance of 150 / 0.05, or 3000 ohms. p.s. Since power is volts times amps, that device is dissipating 7.5 watts.
Power is inversely proportional to resistance. Ohm's law: Current is voltage divided by resistance Power law: Power is voltage times current, therefore power is voltage squared divided by resistance.
All resistances will emit heat energy when a current flows. The heat production rate (or power) can be found by any of these formulas: Power = Current * Voltage Power = Current2 * Resistance Power = Voltage2 / Resistance. Power is given in Watts when Current is in Amps, Voltage in Volts, and Resistance in Ohms.
A: If the transformer is connected to a power input of course it will draw current. The primary is a long wire it has own resistance wrap around an iron core. Of course there will be primary current whether there is a load on the secondary or not.
If the resistance is 1.2k and the current is 0.024 ma, then the voltage is 0.0288 volts. (Voltage = resistance times current) If the voltage is 0.0288V and the current is 0.024 ma, then the power is 0.6912 microwatts. (Power = voltage times current)
Power=current squared times resistance
To find the current in the circuit, you can use the formula: Power = Current^2 * Resistance. Given the values, you can rearrange the formula to solve for current: Current = sqrt(Power / Resistance). Plugging in the values, you get Current = sqrt(2 / 30) which simplifies to approximately 0.27 amperes.
Power = (current) times (voltage)Current = (Power) divided by (voltage)Voltage = (Power) divided by (current)
No, power is not directly proportional to resistance. The power dissipated in a circuit is given by P = I^2 * R, where I is the current flowing through the circuit and R is the resistance. This means that power is proportional to the square of the current but linearly proportional to resistance.
The power dissipated across a resistor, or any device for that matter, is watts, or voltage times current. If you don't know one of voltage or current, you can calculate it from Ohm's law: voltage equals resistance times current. So; if you know voltage and current, power is voltage times current; if you know voltage and resistance, watts is voltage squared divided by resistance; and if you know current and resistance, watts is current squared times resistance.
The formula for calculating current in a circuit when given the values of power and resistance is i p/a.
if the resistance is decreased and the current stays the same, then the power decreases.