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When a crate slides down an incline at a constant velocity, it is experiencing a balanced force situation. The force of gravity pulling it downhill is counteracted by the force of friction acting in the opposite direction. This results in the crate moving steadily without speeding up or slowing down.
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What force is needed to slide a 250-kg crate across the floor at constant velocity if the coefficient of sliding friction between a crate and a horizontal floor is 0.25?
The force needed to slide the crate at constant velocity is equal in magnitude but opposite in direction to the force of friction. The force of friction can be calculated as the product of the coefficient of friction and the normal force acting on the crate (weight of the crate). Therefore, the force needed would be 250 kg * 9.8 m/s^2 * 0.25 = 612.5 N.
Are you agree that your weight is equivalent to the friction force. Why?
No. On a horizontal surface the normal force is equal to weight. If you are moving at constant velocity you only overcome frictional force, which is not equal to weight. This is easier to see on an incline. At some point an object will slide at constant velocity down the incline. This is related to trig functions of the angle of incline multiplied by the weight which is always less than the weight.
A plane inclined at an angle 35 degrees from horizontal if the coefficient of static friction between the crate and the plane is 0.65 will the crate slide down the plane?
Is mgsinΘ > μmgcosΘ ? Is sinΘ > μ cosΘ ? Is sin35º > .65 cos35º Is .573 > .532 => Yes, so crate slides down the plane, no matter what the mass is or acceleration due to gravity
What is the direction of static friction on an incline?
The direction of static friction on an incline is parallel to the surface of the incline and opposite to the direction in which an object would slide down the incline.
What is the angle of slide for the playground equipment?
The angle of slide for the playground equipment is the degree of incline or slope of the slide surface.
What force is needed to slide a 250-kg crate across the floor at constant velocity if the coefficient of sliding friction between a crate and a horizontal floor is 0.25?
The force needed to slide the crate at constant velocity is equal in magnitude but opposite in direction to the force of friction. The force of friction can be calculated as the product of the coefficient of friction and the normal force acting on the crate (weight of the crate). Therefore, the force needed would be 250 kg * 9.8 m/s^2 * 0.25 = 612.5 N.
What is CV type carburetor?
CV stands for (constant velocity). These type carburetors are normally used on motorcycles. A CV carburetor (Constant Velocity) incorporates a vacuum operated slide that varies the venturi size within the carburetor, thus maintaining a constant velocity. The slide also holds a needle that when lifted by the opening slide varies the amount of atomized fuel delivered.
Are you agree that your weight is equivalent to the friction force. Why?
No. On a horizontal surface the normal force is equal to weight. If you are moving at constant velocity you only overcome frictional force, which is not equal to weight. This is easier to see on an incline. At some point an object will slide at constant velocity down the incline. This is related to trig functions of the angle of incline multiplied by the weight which is always less than the weight.
A plane inclined at an angle 35 degrees from horizontal if the coefficient of static friction between the crate and the plane is 0.65 will the crate slide down the plane?
Is mgsinΘ > μmgcosΘ ? Is sinΘ > μ cosΘ ? Is sin35º > .65 cos35º Is .573 > .532 => Yes, so crate slides down the plane, no matter what the mass is or acceleration due to gravity
A constant push of 250 N is needed to slide a crate that weighs 400 N along a 2 meter long ramp If the ramp raises the crate 1 meter what is the ramp's efficiency?
80%
What is the direction of static friction on an incline?
The direction of static friction on an incline is parallel to the surface of the incline and opposite to the direction in which an object would slide down the incline.
What is the angle of slide for the playground equipment?
The angle of slide for the playground equipment is the degree of incline or slope of the slide surface.
If you slide a hockey puck across a frictionless ice rink these must be a horizontal force on it too keep it in the motion?
F=ma constant speed would mean 'a' acceleration is zero thus force zero. The puck would be in equilibrium, and the force would be zero at constant motion. Constant motion is constant velocity including the constant zero velocity.
If you push horizontally on your book with a force of 1 N to make the book slide at constant velocity how much is the force of friction on the book?
The force of friction would also be 1 N, equal in magnitude but opposite in direction to the force you are pushing with. This equal and opposite force of friction is what allows the book to move at a constant velocity.
What is a FCR carburetor?
An FCR carburetor, or Flat Slide Constant Velocity carburetor, is a type of motorcycle carburetor known for its flat slide design that provides improved airflow and throttle response compared to traditional round slide carburetors. It uses a constant velocity mechanism that helps maintain a steady air-fuel mixture across a range of throttle positions, enhancing engine performance. FCR carburetors are popular in performance applications due to their efficiency and tuning capabilities, making them a preferred choice for racing and high-performance motorcycles.
Why is it more difficult to slide a crate starting from rest than it is to keep moving once it is sliding?
It is more difficult to slide a crate starting from rest because static friction exists between the crate and the surface, requiring a greater force to overcome. Once the crate is already sliding, kinetic friction is less than static friction, making it easier to keep moving with a lower force.
A 21.2 kg child descends a slide 3.5 m high and reaches the bottom with a speed?
The answer depends on the incline (slope) of the slide. And, if you want a more realistic answer, a measure of the friction between the child and the slide.
