Because linear momentum is conserved.
Before the shot, the momentum of (gun + bullet) is zero, so it has to be zero after
the shot. The bullet gains forward momentum when fired, so the gun must gain reverse
momentum in order to maintain the zero sum.
By conservation of momentum, the momentum of the gun and bullet system before firing must equal the total momentum after firing. Therefore, the velocity at which the gun recoils can be calculated by using the equation: (mass of bullet * velocity of bullet)/mass of gun = velocity of gun. Substituting the values given: (0.06 kg * 500 m/s) / 5 kg = 6 m/s.
When a gun is fired, the bullet propels forward with a certain momentum due to the force applied by the expanding gases in the gun barrel. According to the principle of momentum conservation, the gun must also experience an equal but opposite momentum in the backward direction. This backward momentum causes the sensation of "kick" felt by the shooter as the gun recoils.
When a bullet is fired from a gun, Newton's third law is applied as the bullet and the gun experience equal and opposite forces. The force pushing the bullet out of the gun is equal to the force pushing the gun backward, causing recoil. This relationship between the bullet and the gun follows the principle of momentum conservation.
When a gun is fired, the projectile goes one way, the gun goes in the opposite direction. That is recoil. Recoil velocity would be the speed at which the gun moves when it recoils. Since the gun is heavier than the projectile, it will recoil more slowly than the projectile moves.
The momentum of the bullet is equal and opposite to the momentum of the gun. Momentum = mv. Bullet =mbvb Gun = mgvg These are equal, with their speeds in opposite directions. mbvb = mgvg vg = vb x mb/mg = vb x (60/5000) = 0.012 vb The recoil speed of the gun is 0.012 the muzzle speed of the bullet. The question says vb is "500ms", which is unclear. If it is meant to indicate "500 meters per second", then the recoil speed is (500 x .012) = 6 m/s.
The plural of recoil is recoils. As in "the gun recoils quite heavily".
Yes.
A gun recoils when fired due to the need to eject the casing and to recycle the pent up gas
There is a part almost all guns called the extractor that, like its name implies, extracts the shell when the bolt of the gun recoils back.
They are exactly equal. The bullet travels faster, and weighs less. The gun recoils more slowly, but weighs much more.
A gun recoils when bullet is fired off the gun.A swimmer pushes the water when he moves forward.
A gun recoils when bullet is fired off the gun.A swimmer pushes the water when he moves forward.
It is part of the receiver. The tang is where the highest point of your grip should be placed. It is a curved portion of the grip that's closest to the slide. This acts as a "pivot" point when the gun recoils.
When a gun is fired a bullet (or cartridge) with a small mass but a very high velocity is ejected. The recoil of the gun is a reaction to this force and is sufficient to push back the person who fired the weapon.
=it is newtons third law of motion which states=="for every action there is an equal and opposite reaction"==when a gun is fired the bullet moves in the forward direction which is action whereas the gun recoils in the backward direction which is the reaction......................=
In an isolated system the total momentum of a system remains conserved. For example If you fire a bullet from Gun , bullet go forward with some linear momentum and in order to conserve the linear momentum the gun recoils
By conservation of momentum, the momentum of the gun and bullet system before firing must equal the total momentum after firing. Therefore, the velocity at which the gun recoils can be calculated by using the equation: (mass of bullet * velocity of bullet)/mass of gun = velocity of gun. Substituting the values given: (0.06 kg * 500 m/s) / 5 kg = 6 m/s.