It depends what substance the refraction is taking place in. You need to know the refractive index, n then you can use the formula (sin(i))/(sin(r)) = n so sin(i) = n * sin(20) and i = arcsin ( n*sin(20) ) or, equivalently: i = sin^-1 ( n*sin(20) ) If you were using a glass block block, then n=1.5 and i = arcsin (1.5*sin(20)) = 30.86588247 = 30.9 degrees (3 s.f.)
The key is to recognize that "the angle of INCIDENCE is equal to the angle of REFLECTION", for an 'Elastic' collision. So the answer is 20 degrees.
The reflection angle will also be 20 degrees from the normal on the other side of the normal in the same plane.
From my experience the only time I've had to do this is when testing angles of incidence and refraction. Usually the angles of incidence are predetermined, say 20, 40 and 60 degree's. A sheet of plain white paper is placed down. A glass block is set in the middle and drawn around. Make sure you draw in your normals. Use a protractor to draw the lines which are are your angles of incidence. Then place the glass block down on the outline and use a line box with a thin slit to make the light as direct as possible. You will notice the light shining through the other side of the glass block, mark these for each incidence angle. Remove your glass block and draw proper lines for the light that was shining out of the block. From here you should be able to draw lines through your glass block outline which will connect the rays of incidence and refraction. Using your protractor you will be able to find the angles of refraction accurate to 1/2 degree i think. Other light experiments such as finding the critical angle which is a limiting angle which if passed will cause total internal reflection to occur. You can find the angle of incidence which causes this to happen in which ever medium you are testing by using the formula: refractive index = 1/sin of critical angle e.g using a diamond of refractive index 2.1 you would have: 2.1 = 1/sin C SinC = 1/2.1 C = Sin^-1 (1/2.1) C = 28.4 degrees (roughly) I hope this helped, however being more specific to which light experiment you want could help!
20 degrees centigrade.
The angle between the incident ray and the reflected ray is equal to the angle between the incident ray and the normal. When the mirror is rotated, the normal also rotates by the same angle. Therefore, the angle between the incident ray and the reflected ray will still be 20 degrees.
40
The key is to recognize that "the angle of INCIDENCE is equal to the angle of REFLECTION", for an 'Elastic' collision. So the answer is 20 degrees.
The reflection angle will also be 20 degrees from the normal on the other side of the normal in the same plane.
The answer depends on knowing what the plane mirror hhas a 20-degree angle relative to!
An angle whose measure is 20 degrees!
to construct an angle of 20 degrees all you have to do is to trisect an angle of 60degrees
The supplement of an angle is found by subtracting the angle from 180 degrees. For 20 degrees, the calculation would be 180 - 20 = 160 degrees. Therefore, the supplement of 20 degrees is 160 degrees.
To find the reference angle for negative 200 degrees, first convert it to a positive angle by adding 360 degrees, resulting in 160 degrees. The reference angle is then found by subtracting this angle from 180 degrees, yielding a reference angle of 20 degrees. Thus, the reference angle for negative 200 degrees is 20 degrees.
100
It is a right angle triangle and its 3rd angle is 70 degrees.
It is: 160 degrees
Between 15 and 20 degrees...