Total momentum before the collision = total momentum after the collision
As a reminder, momentum is the product of velocity and mass.
When traveling at a higher rate of speed you will have more force in case of collision.
In an elastic collision, no kinetic energy is lost, and the relative speed of separation of the objects after the collision is the same as the relative speed before the collision. In an inelastic collision, part of the elastic energy is lost, and the relative speed after the collision is less.
There is more kinetic energy involved in the case of a high-speed collision.
because the high speed collision has more energy that it is using when the damage is occuring love Shanika L. Jackson♥
There is more kinetic energy in the collision involving the high-speed cars than there is in the collision involving the low-speed cars, resulting in a greater amount of force exerted on each car, prompting more damage.
That expression represents average speed during the time.
When traveling at a higher rate of speed you will have more force in case of collision.
The lighter boy will be moved backwards by a force equal to the difference in their masses.
In an elastic collision, no kinetic energy is lost, and the relative speed of separation of the objects after the collision is the same as the relative speed before the collision. In an inelastic collision, part of the elastic energy is lost, and the relative speed after the collision is less.
There's more force exerted in the high speed collision.
There is more kinetic energy involved in the case of a high-speed collision.
because the high speed collision has more energy that it is using when the damage is occuring love Shanika L. Jackson♥
More kinetic energy involved.
There is more kinetic energy in the collision involving the high-speed cars than there is in the collision involving the low-speed cars, resulting in a greater amount of force exerted on each car, prompting more damage.
More kinetic energy involved.
At higher speeds, there is more kinetic energy involved.
It depends on their initial speeds and masses. The speed can be worked out by: mcarucar + mtruckutruck = mbothvboth where u = initial veloicty m = mass v = final veloicty remember u and v are vectors so will have direction!