The power for the first scenario is 10 W (200 J / 20 s = 10 W), while the power for the second scenario is 12.5 W (50 J / 4 s = 12.5 W). Therefore, the second scenario has more power.
Work done is a scalar quantity. It is defined as the product of force and distance in the direction of the force, and does not have a direction associated with it.
Both situations have the same power output of 10 watts, as power is calculated as work done divided by time taken. In this case, 200 J of work done in 20 s and 50 J of work done in 4 s both result in a power output of 10 W.
The situation involving more power is 50 Joules of work done in 4 seconds because power is calculated as work divided by time. In this case, the power would be 12.5 Watts (50 J / 4 s = 12.5 W), while for the first situation it would be 10 Watts (200 J / 20 s = 10 W).
Work done is the measure of energy transfer that occurs when a force causes an object to move a certain distance in the direction of the force. It is calculated as the product of the force applied and the distance moved in the direction of the force. Work done can lead to a change in the energy of an object.
Work done by a force is zero when the force is applied perpendicular to the direction of motion of the object. Another scenario is when the force is applied but there is no displacement of the object.
When a force (no matter how large it may be) is applied to any object without a distance being moved,it cannot be workdone because,workdone = force x distance.
The work is done when the fan moves air, imparting kinetic energy to the air.
Work done is a scalar quantity. It is defined as the product of force and distance in the direction of the force, and does not have a direction associated with it.
When a force (no matter how large it may be) is applied to any object without a distance being moved,it cannot be workdone because,workdone = force x distance.
Both situations have the same power output of 10 watts, as power is calculated as work done divided by time taken. In this case, 200 J of work done in 20 s and 50 J of work done in 4 s both result in a power output of 10 W.
The situation involving more power is 50 Joules of work done in 4 seconds because power is calculated as work divided by time. In this case, the power would be 12.5 Watts (50 J / 4 s = 12.5 W), while for the first situation it would be 10 Watts (200 J / 20 s = 10 W).
Work done by a force is zero when the force is applied perpendicular to the direction of motion of the object. Another scenario is when the force is applied but there is no displacement of the object.
Work done is the measure of energy transfer that occurs when a force causes an object to move a certain distance in the direction of the force. It is calculated as the product of the force applied and the distance moved in the direction of the force. Work done can lead to a change in the energy of an object.
Workdone =force * distance 25N * 2m = 50Nm OR 50joules
Work done on an object is equal to the energy transferred to the object to make it move or undergo a change in its state. This is based on the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. In other words, work done represents the transfer of energy from one form to another.
The work done by a centripetal force is zero because the force is always directed towards the center of the circular motion, while the displacement is perpendicular to the force. This means that the angle between the force and the displacement is 90 degrees, resulting in zero work being done.
The work done is calculated using the formula: Work = Force × Distance × cos(θ). In this case, the force is 10 N, the distance is 2 m, and the angle θ is 0 degrees since the force and distance are in the same direction. Therefore, the work done is 10 N × 2 m × cos(0°) = 20 Joules.