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Is it true to say that a projectile has zero acceleration at its peak. If yes explain if not give a reason?
Yes, it is true to say that a projectile has zero acceleration at its peak.Because the highest height, which the object will reach is known as the peak of the object's motion. The increase of the height will last, until vy = 0.,For more Explanation:Atlas_gondal@yahoo.com
What is the relationship between the horizontal and vertical components of velocity for a projectile launched at an angle between 0 and deg and 90 and deg?
The horizontal and vertical components of velocity for a projectile launched at an angle between 0 and 90 degrees are independent of each other. The horizontal velocity remains constant throughout the motion, while the vertical velocity changes due to the effect of gravity. The initial velocity of the projectile is divided into these two components based on the launch angle.
What are the two types of motion a projectile has?
If you throw ball at an angle above horizontal, you will see the path of the ball looks like an inverted parabola. This is result of the fact that the ball's initial velocity has a horizontal and vertical component. If we neglect the effect of air resistance, the horizontal component is constant. But the vertical component is always decreasing at the rate of 9.8 m/s each second. To illustrate this, let the initial velocity be 49 m/s and the initial angle be 30˚. Horizontal component = 49 * cos 30, Vertical = 49 * sin 30 = 24.5 m/s As the ball rises from the ground to its maximum height, its vertical velocity decreases from 24.5 m/s to 0 m/s. As the ball falls from its maximum height to the ground, its vertical velocity decreases from 0 m/s to -24.5 m/s. Since the distance it rises is equal to the distance it falls, the time that it is rising is equal to the time it is falling. This means the total time is equal to twice the time it is falling. This is the reason that the shape of the ball's path is an inverted parabola. At the maximum height, the ball is moving horizontally. If you do a web search for projectile motion, you will see graphs illustrating this.
Which describes an object in projectile motion Check all that apply. Gravity acts to pull the object down. The object moves in a straight path. The forward velocity of the object is 0 ms. The object a?
Gravity acts to pull the object down, The forward velocity of the object is 0 m/s.
In 0.5 seconds a projectile goes from 0 to 300 meter per second What is the acceleration of the projectile?
The acceleration of the projectile can be calculated using the formula: acceleration = (final velocity - initial velocity) / time Plugging in the values: acceleration = (300 m/s - 0 m/s) / 0.5 s acceleration = 600 m/s^2 Therefore, the acceleration of the projectile is 600 meters per second squared.
What point do all the graphs of the form y equals ax where a equals 0 have in common?
If y = ax and a = 0, then y=0. No matter what x is, y is still 0. Therefore any graph of y=ax (where a=0) will simply be a line at y=0, which is the x-axis.
If a equals positive and b equals negative and c equals zero how many solutions does a Quadratic Equation have?
Two: one is 0, the other is -b/a ax2 + bx + c = 0, but c = 0 ⇒ ax2 + bx + 0 = 0 ⇒ ax2 + bx = 0 ⇒ x(ax + b) = 0 ⇒ x = 0 or (ax + b) = 0 ⇒ x = -b/a
What kind of equation is ax plus b equals 0 in?
A linear equation.
Ax plus bx plus c equals 0?
x = -c/(a+b), provided a+b is not 0
What is a x b x c equals 0?
It's ax squared x bx x c = 0 So (ax x ax) x bx x c = 0 This is the quadratic formula, then you'll move onto the quadratic equation.
What will be the X in terms of a and b if Cos aX equals 1 plus bX and a and b are constants?
a = 0, b = 0.
When Ax plus By equals C passes through the origin will C equal 0 on the graph?
Yes Ax + By = C As the line passes through the origin then x = 0 when y = 0. Substituting gives, 0 + 0 = C therefore C = 0.
What is 3x squared plus 6x-3 equals 8 in the form of Ax squared plus Bx plus C equals 0?
It is: 3x2+6x-11 = 0
If the graph of a linear equation Ax plus By equals C passes through the origin then will C equal 0?
Yes Ax + By = C As the line passes through the origin then x = 0 when y = 0. Substituting gives, 0 + 0 = C therefore C = 0.
Why is 2 to the power 0 is 1?
Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.
How are the graphs of functions defined by rules like y equals ax plus bx different from those of functions with rules like y equals ax plus c?
The graph of the first form passes through the origin while the second does not - unless c = 0.
How do you write this equation 7x-3 equals 3 in ax plus b equals 0 form?
7x - 3 = 3 Subtract 3 from both sides: 7x - 6 = 0 So a = 7 and b = -6
