refer to ph106 book
The backing voltage used in a photomultiplier tube depends on the frequency of light because higher frequency light photons require a higher energy to eject electrons from the cathode, while lower frequency light photons require less energy. By adjusting the backing voltage, the tube can amplify the signal produced by the ejected electrons accordingly.
I assume you are asking in regard to the photoelectric effect. The intensity of the photons can be viewed as the brightness of the light. However, the frequency is the number of wavelengths that pass a certain point in a second. The frequency is also used to determine the energy of the photon (E=hf).
The photoelectric current depends on the intensity of light shining on the surface, the frequency of the light, the type of material the surface is made of, and the energy of the individual photons. Increasing any of these factors can result in a higher photoelectric current.
The intensity of light depends on the amplitude of the light waves, which represents the strength or power of the light wave. The intensity is also affected by the distance the light has traveled from the source, which can cause the light to spread out and decrease in intensity. Additionally, materials through which light passes can affect its intensity through absorption or scattering.
Heinrich Hertz showed that light behaves as particles by demonstrating the photoelectric effect. He observed that low-frequency light could not eject electrons from a metal surface, regardless of intensity, while even low-intensity, high-frequency light could. This discovery provided evidence for the particle-like nature of light, where photons carry specific amounts of energy based on their frequency.
The backing voltage used in a photomultiplier tube depends on the frequency of light because higher frequency light photons require a higher energy to eject electrons from the cathode, while lower frequency light photons require less energy. By adjusting the backing voltage, the tube can amplify the signal produced by the ejected electrons accordingly.
I assume you are asking in regard to the photoelectric effect. The intensity of the photons can be viewed as the brightness of the light. However, the frequency is the number of wavelengths that pass a certain point in a second. The frequency is also used to determine the energy of the photon (E=hf).
No, the kinetic energy of a photoelectron is primarily determined by the frequency of the incident light (photon energy), not the intensity of the light. Increasing the intensity of light will increase the number of photoelectrons emitted but will not change their individual kinetic energies.
The photoelectric current depends on the intensity of light shining on the surface, the frequency of the light, the type of material the surface is made of, and the energy of the individual photons. Increasing any of these factors can result in a higher photoelectric current.
The ultraviolet light contains photons of high energy. these are able to excite the atoms. which during the process of de-excitation can emit frequencies , which are detectable by normal eye. So it depends upon frequency of light..
it measures the intensity of light of a specified frequency
Intensity (brightness) and energy (frequency).
The intensity of light depends on the amplitude of the light waves, which represents the strength or power of the light wave. The intensity is also affected by the distance the light has traveled from the source, which can cause the light to spread out and decrease in intensity. Additionally, materials through which light passes can affect its intensity through absorption or scattering.
Heinrich Hertz showed that light behaves as particles by demonstrating the photoelectric effect. He observed that low-frequency light could not eject electrons from a metal surface, regardless of intensity, while even low-intensity, high-frequency light could. This discovery provided evidence for the particle-like nature of light, where photons carry specific amounts of energy based on their frequency.
You will need to have the right formula. The best one to use would be wavelength=frequency/speed of light. to find energy you would need energy=frequency*h. And intensity=power/area.
More important for what. If you use the analogy with sound, the frequency of light is the pitch of the sound (also the frequency of the sound waves), and the intensity is how loud it is. Both are equally important, but for different reasons. Sometimes you want a low frequency, sometimes you want a high frequency. Sometimes you want low intensity, others high intensity. Depends what you want it for.
Intensity is a measure of the brightness or saturation of a color. Typically, brighter or more vibrant colors such as red, orange, and yellow are considered to have greater intensity compared to darker or more muted colors like blue, green, or purple.