Newton's rings are created by the destructive and constructive interference between the light waves. Destructive is when one wave is at a crest (high point) and one is at a trough (low point) and they cancel each other out. Constructive is when both rays are at a crest or trough and they amplify each other. The dark areas (like the cenrte of the rings) are created by destructive interference.
At the point of contact the lens and the glass plate, the thickness of the film is effectively zero but due to reflection at the lower surface of air film from denser medium, an additional path difference of Lemda/2 is introduced. consequently, the centre of newton ring is dark due to destructive interference.
No, the distance between two adjacent bright and dark rings in Newton's rings pattern is not equal. The spacing between the rings decreases as we move from the center outwards, due to the curvature of the lens. This pattern is a result of the varying film thickness of air between the lens and the flat glass plate.
When a planoconcave lens is placed in Newton's ring experiment, the center is thinner than the edges due to the concave shape of the lens. This causes a change in the path length of light, leading to destructive interference at the center. As a result, the central rings appear to converge towards the center as they collapse due to the interference pattern created by the combination of the lens and the light waves.
The fringe width of Newton rings is the distance between two consecutive bright or dark fringes observed when a plano-convex lens is placed on a flat glass plate. It is given by the formula [ w = \lambda \cdot R / (D - R) ], where ( \lambda ) is the wavelength of light, ( R ) is the radius of curvature of the lens, and ( D ) is the diameter of the bright ring.
Radius of curvature in Newton's rings is the radius of the curvature of the wavefront at the point where interference fringes are observed. It is calculated by measuring the diameter of the nth dark ring and using the formula R = (n * λ * D) / (2 * δ), where R is the radius of curvature, n is the order of the ring, λ is the wavelength of light, D is the distance between the lens and the glass plate, and δ is the diameter of the nth dark ring.
At the point of contact the lens and the glass plate, the thickness of the film is effectively zero but due to reflection at the lower surface of air film from denser medium, an additional path difference of Lemda/2 is introduced. consequently, the centre of newton ring is dark due to destructive interference.
Because the intensity is maximum at the centre. Therefore the central spot is bright and not dark.
No, the distance between two adjacent bright and dark rings in Newton's rings pattern is not equal. The spacing between the rings decreases as we move from the center outwards, due to the curvature of the lens. This pattern is a result of the varying film thickness of air between the lens and the flat glass plate.
newtons ring is formed due to the consequtive circle of different radius of bright and dark in which the centre is dark
When a planoconcave lens is placed in Newton's ring experiment, the center is thinner than the edges due to the concave shape of the lens. This causes a change in the path length of light, leading to destructive interference at the center. As a result, the central rings appear to converge towards the center as they collapse due to the interference pattern created by the combination of the lens and the light waves.
becaus thicknes of thin film is 0 and wavelenth is l so according to formula 2t-(l/2 ) destructive inteference will ocur and path difference is odd integral multiple of half of wavewavelenth
when dust particles come in contect of plano convex lence.
Newton Center - MBTA station - was created in 1959.
I think a ring with no center is a sphere......?????...yes?..no?
No. For example, a ring has a center of gravity in the center of the ring, not on any part of the ring.
the newton's rings are formed due to the phenomenon of thin film interference. here, the condition for constructive interference(the ring appearing bright) is that the optical path difference between interfering waves should be an integral multiple of the wavelength. the optical path difference is given by 2t-(l/2) if t is the thickness of the air film at that point and l is the wavelength of light. at the central point, the lens touches the surface so thickness t=0. thus the optical path difference is simply l/2, which is the condition for destructive interference, not constuctive interference. so the central spot has to always be dark.
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