They have a large number of free electrons. Having lots of free electrons make it easier to move the electrons around this creates a good electric current. They best conductors (silver, copper, gold and aluminum ). Cost, weight and ease of handling also make it a more popular material.
It is a poor conductor.
No, bitumen is not a good conductor of electricity. It is considered to be an insulator rather than a conductor.
Galena is not a good conductor of electricity. However, it is a good conductor of heat due to its high thermal conductivity.
Graphite is brittle but a good conductor of electricity.
Duct tape is not a good conductor of heat. Its composition and thickness make it a poor conductor, so it does not readily transfer heat.
cu,ag, and au are all in what group
Cu + AgNO3 → Ag + Cu(NO3)2 In this reaction, copper (Cu) is more reactive than silver (Ag), so it will replace silver in the compound AgNO3, resulting in the formation of silver metal and copper nitrate.
The balanced equation for the reaction is: Cu + 2AgNO3 -> Cu(NO3)2 + 2Ag Calculate the molar mass of Cu and Ag (Cu = 63.55 g/mol, Ag = 107.87 g/mol). Using the molar ratio of Cu to Ag (1:2), convert the mass of Cu to moles, then use the molar ratio to find the moles of Ag produced. Finally, convert moles of Ag to grams using the molar mass of Ag to find the grams of silver produced.
cu(II) + 2agcl --> 2ag+cucl2
cu,ag, and au are all in what group
Copper (Cu) does not form more than one type of cation.
The addition of Cu to a Ni conductor can improve its mechanical properties and resistance to corrosion. This is because Cu forms solid solution with Ni, enhancing the overall performance of the material. However, excessive amounts of Cu can negatively affect the electrical conductivity of the Ni conductor.
The correct answers are: Ag+ and Cu+2.
To calculate the percent yield of silver (Ag) in the reaction, we first need to determine the theoretical yield of Ag based on the amount of Cu used. The balanced chemical equation shows that 1 mole of Cu produces 2 moles of Ag. The molar mass of Cu is approximately 63.55 g/mol, and that of Ag is about 107.87 g/mol. From 12.7 g of Cu, we can calculate the moles of Cu: [ \text{Moles of Cu} = \frac{12.7 \text{ g}}{63.55 \text{ g/mol}} \approx 0.199 \text{ moles} ] Since 1 mole of Cu produces 2 moles of Ag, the theoretical yield of Ag would be: [ 0.199 \text{ moles Cu} \times 2 \text{ moles Ag/mole Cu} \times 107.87 \text{ g/mol} \approx 43.0 \text{ g Ag} ] Now, using the actual yield of 38.1 g Ag, the percent yield can be calculated as: [ \text{Percent Yield} = \left(\frac{38.1 \text{ g}}{43.0 \text{ g}}\right) \times 100 \approx 88.8% ] Thus, the percent yield of silver in this reaction is approximately 88.8%.
Copper (Cu), silver (Ag), and gold (Au) are transition metals that have high electrical conductivity and are commonly used in jewelry and electrical wiring. Aluminum (Al) is a lightweight metal commonly used in construction due to its strength and resistance to corrosion.
Copper (Cu) is the most common metal used in conducting wire. If you have the money the best conductor (excluding super cooled super conductors) would be pure silver (Ag).
The requested equation is Cu + AgNO3 -> CuNO3 + Ag or Cu + 2 AgNO3 -> Cu(NO3)2 + 2 Ag, depending on whether copper forms its (II) or (I) cations.