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It increases the drag coefficient (dc)
.
Say freefall terminal velocity (vf) = 60 metres per second
Say landing terminal velocity (vl) = 6 metres per second
Mass of freefaller (m) = 70 kg
Acceleration due to gravity (g) = 10 (m/s)/s (approx)
.
Force down (newtons)= mass * acceleration due to gravity
Force up (newtons) = drag coefficient * velocity squared
Terminal velocity is where forces balance:
m * g = dc * v2
.
Freefall velocity (parachute closed) = 60 metres per second
m * g = dc * (vf)2
then:
dc = (m * g) / (vf)2
dc = 700 / 3600
dc = 0.194 (prior to parachute opening)
.
Landing velocity (parachute open) = 6 metres per second
dc = (m * g) / (vl)2
dc = 700 / 36
dc = 19.44 (with parachute open)
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