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What is a rapid movement of excess charge from one place to another?

A rapid movement of excess charge from one place to another is known as an electrical discharge. This phenomena can result in lightning, electric sparks, or discharge in electronic devices.


What must there be for a flow of charge from one place to another?

For a flow of charge from one place to another, there must be a potential difference or voltage present. This potential difference creates an electric field that exerts a force on charged particles, causing them to move and create an electric current. Additionally, there must be a conductor or medium through which the charged particles can flow.


How can the electrical potential energy of a charged particle in an electric field be increased?

THIS IS A GOOD QUESTION IF WE PLACE THE CHARGE IN THE ELECTRIC FIELD AT A DISTANCE R FROM THE ELECTRIC FIELD AND PLACED THE ANOTHER POINT CHARGE AT A ANOTHER DISTANCE r WHERE R IS GRATER THAN THE SMALL R THEN THE ELECTRIC FIELD AT r IS MORE THAN THE ELECTRIC FIELD AT POINT R.ORWE CAN SAY THAT IF THE CHARGE IS PLACED IN THE DIRECTION OF ELECTRIC FIELD THAN ITS ELECTROSTATIC POTENTIAL ENERGY WILL DECREASE OR WHEN IN DIRECTION OPPOSITE THAN VICEVERSA


What is the movement of static charge from one place to another?

Static Discharge:Perhaps you see a spark jump between your hand and the doorknob. The spark is an example of an electric discharge. An electric discharge is the movement of static charge from one place to another. The spark you saw was the result of a static charge moving between your hand and the doorknob.


What has potential energy?

Potential energy is a energy stored within a system as a result of the position or configuration of the different parts of that system.The types of potential energy are gravitational potential energy, which is energy due to height, and elastic potential energy, which is energy involved with a stretched or compressed spring.

Related Questions

What is the rapid movement of excess electrons from place to another?

electric discharge


What is meant by silent electric discharge?

electric dischar thattaks place in air or gases due to high voltageg


What is a rapid movement of excess charge from one place to another?

A rapid movement of excess charge from one place to another is known as an electrical discharge. This phenomena can result in lightning, electric sparks, or discharge in electronic devices.


What is the definition of voltage?

Difference in potential between two points. Like the voltage of an energizer AA battery is 1.5 volts BETWEEN its terminals. If you place two AA batteries in a flashlight, the voltage of the series combination of AA batteries from one tip to the other is now 3 volts.


What is the difference between static electricity and electric discharge?

Static electricity is the accumulation of electric charge on the surface of an object, while electric discharge is the sudden flow of electricity between two charged objects or points at different voltages. Static electricity is usually a temporary imbalance of charges, while electric discharge results in the equalization of charges, often in the form of sparks or lightning.


The buildup of electric charges in one place?

The buildup of electric charges in one place can lead to static electricity. This accumulation of charges occurs when electrons are transferred from one surface to another, creating an imbalance that can result in sparking or electric discharge. It is commonly experienced when rubbing two objects together, such as when shuffling feet on a carpet.


What energy conversions that take place of a rubber powered aeroplane to fly?

Potential to kinetic to electric energy conversion takes place when a rubber powered aeroplane flies.


What does electrical potential mean?

Electric potential is like electric potential energy, except electric potential energy requires that you have at least two charged particles: one charged particle (can be considered to be stationary) to produce the electric field and another charged particle to be affected by that electric field. If both charged particles are positively charged, then when you move the nonstationary charged particle closer to the stationary charged particle, potential energy of the system increases, because the charged particles naturally want to repel. However, let's say you remove that nonstationary charged particle and are left with just the single charged particle. There is no more potential energy in the system, because there is no other charged particle to be acted upon by the electric field. However, the single charged particle still emits an electric field. This field is what creates "electric potential." Even though there is no second particle in the system, if you were to place a second particle into the system (let's call it a test particle), its potential energy would be equal to the electric potential multiplied by the charge of the test particle. U = kq1q2/r (electric potential energy with 2 charges, where the 0 of potential energy is infinitely far away) V = kq1/r (electric potential requiring only 1 charge) V = U/q2 (electric potential is potential energy without the second charge) U = Vq2 (electric potential energy is electric potential multiplied by second charge) There is also a concept called gravitational potential, where it's gravitational potential energy divided by the test mass. It can be a negatively charged particle. In that case, electric potential decreases as you get closer to the negatively charged particle. Even though electric potential decreases, if you have two negatively charged particles, electric potential energy increases as you move the 2nd negative charge closer to the first charge. This is because multiplying 2 negative charges makes a positive: U = k(-q1)*(-q2)/r = kq1q2/r (assuming q1 and q2 are the charge magnitudes) So in this case, it's a little weird because that's how the math works. Nature has a tendency to reduce potential energy, but potential is different and doesn't work the same way. However if the test charge was positive, the sign of electric potential energy will be the same as electric potential with respect to location. V = k(-q1)/r = -kq1/r U = k(-q1)(q2)/r = -kq1q2/r Potential energy is not the same as potential! They are related, but don't get them confused. Energy is measured in Joules. Potential is measured in Volts. Completely different units. Volts = Number of Joules / Number of Coulombs. Electric Potential = Electric Potential Energy / Charge of Test Particle


What Electrical potential energy?

Electric potential is like electric potential energy, except electric potential energy requires that you have at least two charged particles: one charged particle (can be considered to be stationary) to produce the electric field and another charged particle to be affected by that electric field. If both charged particles are positively charged, then when you move the nonstationary charged particle closer to the stationary charged particle, potential energy of the system increases, because the charged particles naturally want to repel. However, let's say you remove that nonstationary charged particle and are left with just the single charged particle. There is no more potential energy in the system, because there is no other charged particle to be acted upon by the electric field. However, the single charged particle still emits an electric field. This field is what creates "electric potential." Even though there is no second particle in the system, if you were to place a second particle into the system (let's call it a test particle), its potential energy would be equal to the electric potential multiplied by the charge of the test particle. U = kq1q2/r (electric potential energy with 2 charges, where the 0 of potential energy is infinitely far away) V = kq1/r (electric potential requiring only 1 charge) V = U/q2 (electric potential is potential energy without the second charge) U = Vq2 (electric potential energy is electric potential multiplied by second charge) There is also a concept called gravitational potential, where it's gravitational potential energy divided by the test mass. It can be a negatively charged particle. In that case, electric potential decreases as you get closer to the negatively charged particle. Even though electric potential decreases, if you have two negatively charged particles, electric potential energy increases as you move the 2nd negative charge closer to the first charge. This is because multiplying 2 negative charges makes a positive: U = k(-q1)*(-q2)/r = kq1q2/r (assuming q1 and q2 are the charge magnitudes) So in this case, it's a little weird because that's how the math works. Nature has a tendency to reduce potential energy, but potential is different and doesn't work the same way. However if the test charge was positive, the sign of electric potential energy will be the same as electric potential with respect to location. V = k(-q1)/r = -kq1/r U = k(-q1)(q2)/r = -kq1q2/r Potential energy is not the same as potential! They are related, but don't get them confused. Energy is measured in Joules. Potential is measured in Volts. Completely different units. Volts = Number of Joules / Number of Coulombs. Electric Potential = Electric Potential Energy / Charge of Test Particle


What must there be for a flow of charge from one place to another?

For a flow of charge from one place to another, there must be a potential difference or voltage present. This potential difference creates an electric field that exerts a force on charged particles, causing them to move and create an electric current. Additionally, there must be a conductor or medium through which the charged particles can flow.


How can the electrical potential energy of a charged particle in an electric field be increased?

THIS IS A GOOD QUESTION IF WE PLACE THE CHARGE IN THE ELECTRIC FIELD AT A DISTANCE R FROM THE ELECTRIC FIELD AND PLACED THE ANOTHER POINT CHARGE AT A ANOTHER DISTANCE r WHERE R IS GRATER THAN THE SMALL R THEN THE ELECTRIC FIELD AT r IS MORE THAN THE ELECTRIC FIELD AT POINT R.ORWE CAN SAY THAT IF THE CHARGE IS PLACED IN THE DIRECTION OF ELECTRIC FIELD THAN ITS ELECTROSTATIC POTENTIAL ENERGY WILL DECREASE OR WHEN IN DIRECTION OPPOSITE THAN VICEVERSA


How electrical potential produce?

Electric potential is like electric potential energy, except electric potential energy requires that you have at least two charged particles: one charged particle (can be considered to be stationary) to produce the electric field and another charged particle to be affected by that electric field.If both charged particles are positively charged, then when you move the nonstationary charged particle closer to the stationary charged particle, potential energy of the system increases, because the charged particles naturally want to repel.However, let's say you remove that nonstationary charged particle and are left with just the single charged particle. There is no more potential energy in the system, because there is no other charged particle to be acted upon by the electric field. However, the single charged particle still emits an electric field. This field is what creates "electric potential." Even though there is no second particle in the system, if you were to place a second particle into the system (let's call it a test particle), its potential energy would be equal to the electric potential multiplied by the charge of the test particle.U = kq1q2/r (electric potential energy with 2 charges, where the 0 of potential energy is infinitely far away)V = kq1/r (electric potential requiring only 1 charge)V = U/q2 (electric potential is potential energy without the second charge)U = Vq2 (electric potential energy is electric potential multiplied by second charge)There is also a concept called gravitational potential, where it's gravitational potential energy divided by the test mass.It can be a negatively charged particle. In that case, electric potential decreases as you get closer to the negatively charged particle. Even though electric potential decreases, if you have two negatively charged particles, electric potential energy increases as you move the 2nd negative charge closer to the first charge. This is because multiplying 2 negative charges makes a positive:U = k(-q1)*(-q2)/r = kq1q2/r (assuming q1 and q2 are the charge magnitudes)So in this case, it's a little weird because that's how the math works. Nature has a tendency to reduce potential energy, but potential is different and doesn't work the same way.However if the test charge was positive, the sign of electric potential energy will be the same as electric potential with respect to location.V = k(-q1)/r = -kq1/rU = k(-q1)(q2)/r = -kq1q2/rPotential energy is not the same as potential! They are related, but don't get them confused. Energy is measured in Joules. Potential is measured in Volts. Completely different units.Volts = Number of Joules / Number of Coulombs.Electric Potential = Electric Potential Energy / Charge of Test Particle