Glass is an insulator and will not allow excess charge to leave, as insulators prevent electrons from flowing freely from atom to atom.
Glass is an insulator and will not allow excess charge to leave, as insulators prevent electrons from flowing freely from atom to atom.
Increase one charge by four times. APEX.
no gauss low is only applicable for closed paths. a plane sheet is not a closed path. for applying gauss law the charge must be inside the closed loop or path... ========================== I'll say "yes". Gauss' law says that the electric flux through a closed surface is proportional to the amount of charge inside the closed surface. The shape of the surface doesn't matter, and the shape of the charge distribution inside it doesn't matter either. If a closed surface encloses a part of a sheet of charge, then the flux through the surface is proportional to the amount of charge that's on the part of the sheet inside the surface. That doesn't bother me at all.
An equipotential surface has the same value of potential. Thus, work done would be zero. Work done = Charge X Potential difference
Gauss's Law states that the electric flux from a closed surface matches the amount of the enclosed charge divided by the permittivity.
Glass is an insulator and will not allow excess charge to leave, as insulators prevent electrons from flowing freely from atom to atom.
Yes the Earth has a vertical electric field that points down. So if you were to try and calculate the amount of excess charge on the Earth's surface, you would get a negative value.
Increase one charge by four times. APEX.
It's all chemical energy with a small amount of surface charge.
no gauss low is only applicable for closed paths. a plane sheet is not a closed path. for applying gauss law the charge must be inside the closed loop or path... ========================== I'll say "yes". Gauss' law says that the electric flux through a closed surface is proportional to the amount of charge inside the closed surface. The shape of the surface doesn't matter, and the shape of the charge distribution inside it doesn't matter either. If a closed surface encloses a part of a sheet of charge, then the flux through the surface is proportional to the amount of charge that's on the part of the sheet inside the surface. That doesn't bother me at all.
its mass will increase by an amount too small to measure directly
An equipotential surface has the same value of potential. Thus, work done would be zero. Work done = Charge X Potential difference
Gauss's Law states that the electric flux from a closed surface matches the amount of the enclosed charge divided by the permittivity.
As you move left to right (in one period of the Periodic Table) the amount of protons in the nucleus increases. More protons means a greater positive charge on the nucleus, which is what "core charge" represents.
If the lease is up, you can legally evict if they refuse to pay the new amount using partials as the reason. if they want to continue renting it they have no choice. If no lease, you can legally charge whatever you want and they either pay the full amount or go.
No, the charge held by a solid metal sphere and a hollow sphere of the same diameter would be the same. In both cases, the charge resides on the outer surface of the sphere due to the principle of electrostatic equilibrium.
equal but opposite