The horizontal component of velocity remains constant for an object in projectile motion because there are no horizontal forces acting on the object once it is in motion. In the absence of air resistance and other external forces, the object will continue to move horizontally at a constant speed.
The horizontal speed of the projectile remains constant as there is no force acting in the horizontal direction to change it. Therefore, the horizontal speed of the projectile after 3 seconds will remain at 4 m/s.
Changing the angle of an object's motion will affect both the horizontal and vertical components of its velocity. For example, if you increase the angle of launch for a projectile, it will have a greater vertical component and a shorter horizontal component. This will result in a change in the overall velocity vector of the object.
When a body is thrown horizontally with uniform speed, there is no change in the horizontal velocity, so the horizontal component of acceleration is zero. The only acceleration acting on the body is due to gravity in the vertical direction.
The horizontal component of velocity for a projectile is not affected by the vertical component at all. Horizontal component is measured as xcos(theta) Vertical component is measured as xsin(theta) Whereas theta is the angle, and x is the magnitude, or initial speed.
The horizontal component of the initial velocity of the ball is the velocity in the horizontal direction at the moment the ball is launched. It represents the speed and direction at which the ball is moving side-to-side.
The horizontal speed of the projectile remains constant as there is no force acting in the horizontal direction to change it. Therefore, the horizontal speed of the projectile after 3 seconds will remain at 4 m/s.
Changing the angle of an object's motion will affect both the horizontal and vertical components of its velocity. For example, if you increase the angle of launch for a projectile, it will have a greater vertical component and a shorter horizontal component. This will result in a change in the overall velocity vector of the object.
When a body is thrown horizontally with uniform speed, there is no change in the horizontal velocity, so the horizontal component of acceleration is zero. The only acceleration acting on the body is due to gravity in the vertical direction.
The horizontal component of velocity for a projectile is not affected by the vertical component at all. Horizontal component is measured as xcos(theta) Vertical component is measured as xsin(theta) Whereas theta is the angle, and x is the magnitude, or initial speed.
The horizontal component of the initial velocity of the ball is the velocity in the horizontal direction at the moment the ball is launched. It represents the speed and direction at which the ball is moving side-to-side.
The horizontal velocity component of the ball can be calculated using the formula: horizontal velocity = initial velocity * cos(angle). Substituting the values, we get: horizontal velocity = 31 m/s * cos(35 degrees) ≈ 25.3 m/s.
In projectile motion, the horizontal component of motion is constant and does not change, while the vertical component is affected by gravity causing it to accelerate downwards. This results in a parabolic path of the projectile where the horizontal distance traveled is determined by the initial velocity and angle of projection, while the vertical distance is influenced by gravity.
Constant speedThe graph you described is a speed-time plot. If the line is horizontal, that indicates no change in speed over time. In other words, there is no acceleration (acceleration is zero), since there is no change in speed.
A projectile has the least speed at its highest point in the trajectory, also known as the apex. At this point, the vertical speed component is zero, while the horizontal speed component remains constant if no air resistance is considered.
If there wouldn't be air resistance and gravity is the only thing that is effecting the projectile, the projectile will start to fall but it horizontal velocity will remain the same. So it would slow down, it would only change height.
The horizontal velocity component of the ball can be found by using the equation: horizontal velocity = initial velocity * cos(angle). In this case, the initial velocity is 26 m/s and the angle is 30 degrees. Plugging in the values, we get: horizontal velocity = 26 m/s * cos(30) ≈ 22.5 m/s.
The graph you described is a speed-time plot. If the line is horizontal, that indicates no change in speed over time. In other words, there is no acceleration (acceleration is zero), since there is no change in speed.