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Why is the value of acceleration due to gravity at the poles is greater than at the equator?
I think there are two reasons:
- Gravitational attraction between two masses is inversely proportional to the square of the distance between their centers of mass, and since the earth is not quite a sphere, you're closer to the center of the earth when you're at one of the poles than you are at the equator.
- The earth is rotating at one degree every four minutes, which means that everything on the equator is circling the earth at a linear speed of about 1040 miles per hour. The resulting inertia, which would fling everything into space like an object on a spinning turntable if not for gravity, gets subtracted from gravity.
What else can I help you with?
Where is acceleration due to gravity greater?
Acceleration due to gravity is greater at the surface of the Earth compared to higher altitudes or in outer space. This is because the force of gravity is stronger closer to the center of mass of an object, such as the Earth.
Is there any difference between the value of g at the equator and the poles?
Yes, there is a difference in the value of acceleration due to gravity (g) at the equator and the poles. This is because the Earth is not a perfect sphere and has an oblate shape. At the equator, the centrifugal force due to the Earth's rotation reduces the effective gravity and makes g slightly smaller compared to the poles where this effect is minimal.
Why does the weight of an object change when it is moved from the equator to the poles?
The weight of an object changes when it is moved from the equator to the poles due to the variation in gravitational force caused by the Earth's rotation. The force of gravity is slightly stronger at the poles compared to the equator, leading to a small change in weight.
What is the acceleration due to gravity at 49 degrees north latitude?
The acceleration due to gravity is not a constant across the face of the earth, as is astutely suggested from the nature of the question. The acceleration due to gravity on earth is given by g , and it is about 9.789 m/sec2 at the equator and about 9.823 m/sec2 at the poles. The observer might conclude with a bit of thought that the effect of gravity at the poles is a bit higher because of the shape of the earth, which is sometimes termed an oblate spheroid by astrophysicists. The earth is flattened up top and down bottom, and is a bit "fatter" in the middle. That means that a body on the equator is farther from the effective center of pull of gravity of earth. It will weigh less on the equator. And more on the poles where gravity is higher. At 49 degrees north latitude, the value of g is some 9.8707 m/sec2 there. Note that the general value often given for g is some 9.8 m/sec2, and it is applied for much work in "regular" mechanics.
What is the value of acceleration due to gravity g in Dublin Ireland?
The acceleration of gravity (9.80 meters per second squared) does vary a bit with latitude because of the effects of centripetal acceleration as well as differences in the Earth's polar and equatorial diameters.1 But the variance isn't noticeable until the third significant figure. The acceleration due to gravity will be somewhat less in Dublin than at the equator because Dublin's latitude is 53 degrees, 20 minutes North Latitude, closer to the pole than the equator. To calculate a more precise value (more precise than just 9.80 m/s2) would require you to know the radius of the Earth at your location, since g = GMe/Re, where G is the universal gravitation constant, Me is the mass of the Earth, and Re is the radius of the Earth. From that you would substract the centripetal acceleration, which can also be calculated based upon your latitude. (Which is an answer to another question that hasn't been asked yet!) _________ 1. The Earth is not a perfect sphere. The equatorial diameter is greater than the polar diameter. Hence, g will be slightly greater at the poles than at the equator. And because the Earth rotates, the acceleration of gravity will be reduced by the centripetal acceleration, which is greatest at the equator. So, if oyu want to lose weight, move from Dublin to Ecuador.
Does gravity have a stronger pull at the eatrh poles then it does on the equator?
no, but the electromagnetic field of the earth does.
Where is acceleration due to gravity greater?
Acceleration due to gravity is greater at the surface of the Earth compared to higher altitudes or in outer space. This is because the force of gravity is stronger closer to the center of mass of an object, such as the Earth.
Is there any difference between the value of g at the equator and the poles?
Yes, there is a difference in the value of acceleration due to gravity (g) at the equator and the poles. This is because the Earth is not a perfect sphere and has an oblate shape. At the equator, the centrifugal force due to the Earth's rotation reduces the effective gravity and makes g slightly smaller compared to the poles where this effect is minimal.
Why would an object way less at the equator than at the poles?
Not for sure but it seems like there would be more gravity at the equator than at the poles. The earth rotates and creates a centrifugal acceleration at the equator the counters the force of gravity. acceleration due to gravity =GM/R2 acceleration due to rotation =V2/R So gravity at the equator is GM/R2 - V2/R
Why is gravity stronger at the poles than the equator?
Gravity is stronger at the poles than the equator because of the Earth's shape. The Earth is an oblate spheroid, meaning it is slightly flattened at the poles and bulges at the equator due to its rotation. This bulging at the equator causes objects to be farther away from the center of the Earth, resulting in weaker gravitational pull compared to the poles.
How does the acceleration of gravity depend on it's distance from the center of the Earth?
acceleration due to gravity is given by, g=GM/R2 Hence distance from the earth increases g decreases and viceversa. So g at poles is greater than g at equator.
Is value of g is greater at the poles or at equator?
The expression for acceleration due to gravity isge=GMe/r2Acceleration due to gravity is inversely proportional to the square of the distance between the center of the Earth and the object. The acceleration due to gravity produced in an object on the surface of the Earth is dependent on the radius of the Earth. Earth is not a perfect sphere (slightly bulging out at the equator) its radius decreases as we move from the equator to the poles. At the equator and at sea level its value is about 9.78 m/s2 and at the poles it is 9.83 m/s2. Its mean value is taken as 9.8 m/s2 for all calculations.
Gravity is greater at the what?
Gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles. This means an object will weigh about 0.5% more at the poles than at the Equator.
How the gravitational acceleration will change when you move from equator to north or south pole on the surface of earth?
The gravitational acceleration will decrease slightly as you move from the equator to the poles due to the Earth's shape (oblate spheroid). This is because the centrifugal force is greater at the equator compared to the poles, which causes a slight decrease in the net gravitational force experienced at the equator.
Why does the weight of an object change when it is moved from the equator to the poles?
The weight of an object changes when it is moved from the equator to the poles due to the variation in gravitational force caused by the Earth's rotation. The force of gravity is slightly stronger at the poles compared to the equator, leading to a small change in weight.
Will a pendulum swing faster at the equator than at the poles?
Well, I think it will swing faster in the equator than at the poles because T=sq. root l/q says that when the gravity increases, the time decreases and when the gravity decreases time increases. Thus it will swing slower at the poles than in the equator
Gravity is greater at the?
poles
