Why light ray retrace its path when passes through center of curvature of a concave mirror?

Answer 1

Because the center of curvature is defined to be in the direction of the normal. remember that a reflecting angle of light, relative to the normal, equals minus the angle of the beam that hit the mirror, relative to the normal. since the center of curviture is in the direction of the normal. A beam going through it would be with an angle of zero, and there for return with an angel of (minus) zero. In other words it comes back in the same direction.

Answer 2

The light ray passing from the centre of curvature is perpendicular or normal to the the sphere of which the concave mirror is a part . because the ray from centre to mirror will act as the radius and we know that radius is perpendicular to the tangent at the point of contact. hence angle of incidence = 0 degree , so angle of refraction will also be 0 degree , hence the ray will retrace its path .

Answer 3

When a light ray passes through the center of curvature of a concave mirror, it retraces its path because it reflects back on itself due to the mirror's curvature. The incident ray and reflected ray form equal angles with the mirror's normal at the point of incidence, resulting in the light retracing its original path.

Answer 4

when a ray of light strikes a solid surface , the light is not absorbed by it it is reflected back. this is reflected ray

Answer 5

The light ray passing through centre of curvature of a concave mirror is perpendicular to the sphere of which the mirror is a part. so it retraces its path