Because the material does not disappear, it breaks down to another material.
And in the process relases some radiation.
No. In two half-lives, a radioactive isotope will decay to one quarter of its original mass. In one half-life, one half of the mass decays. In the next half-life, one half of the remaining mass decays, and so on and so forth. At each half-life point, you would see 0.5, 0.25, 0.125, 0.0625, etc. remaining. The logarithmic equation is... AT = A0 2(-T/H)
After 133.5 days, there will be 0.125 mg of the 2 mg sample of iron-59 remaining. This can be calculated by taking into account each half-life period (44.5 days) and calculating the remaining amount after 3 half-lives (133.5 days).
You would have to wait for 2000 years for the mass to decrease to 50 grams (one half-life) and another 2000 years to decrease to 25 grams (two half-lives). So, in total, you would have to wait 4000 years for the mass to decrease to 25 grams.
If you take one day equal to 24 hours, then 1 day constitutes 2 Half lives. Mass of isotope left after 12 hours=10/2=5g Mass of isotope left after 2 half lives or 1 day=5/2=2.5g.
The acceleration will be cut in half. This is because, according to Newton's second law (F = ma), if force remains constant while mass doubles, the acceleration will be halved.
1.48 * If 0.0105 g of a radioisotope remained after six half-lives, then the original mass was 0.672g.
.0463g*25 =1.4816g
I think it´s mass.
After 3 half-lives, the remaining mass is ( \frac{1}{8} ) of the original mass. So if the original mass is 12.5 mg, the final mass after 3 half-lives would be ( 12.5 , \text{mg} \times \frac{1}{8} = 1.56 , \text{mg} ).
The original mass was 3.728 g. Each half-life reduces the mass by half, so after four half-lives, ( \left( \frac {1}{2} \right)^4 = \frac{1}{16} ) of the original mass remains. Therefore, the original mass can be calculated as 0.233 g * 16 = 3.728 g.
3.79
0.672
Since the element has a half-life of 1000 years, it will take two half-lives for the mass to decrease to 5 grams from 20 grams. Two half-lives equal 2000 years, so you would have to wait 2000 years for the mass to decrease to 5 grams.
After four half-lives, the amount of parent material remaining can be calculated using the formula ( \text{Remaining mass} = \text{Initial mass} \times \left(\frac{1}{2}\right)^n ), where ( n ) is the number of half-lives. For an initial mass of 100 g, after four half-lives, the calculation is ( 100 , \text{g} \times \left(\frac{1}{2}\right)^4 = 100 , \text{g} \times \frac{1}{16} = 6.25 , \text{g} ). Thus, 6.25 g of the parent material remains after four half-lives.
A half-life is the amount of time it takes for half of the material to decay. So if you started with 80g After 1 half-life you would have 40 g After 2 half-lives you would have 20 g After three half-lives you would have 10 g
The half-life of an atom is how long it takes for half of the atom's mass to radioactively decay. This occurs exponentially; therefore, after 2 of the atom's half-lives have passed, 3/4 of the atom will have decay (half during the first half-life, then half of the remaining mass, or one quarter, during the second).
A radioactive substance halves in size and activity after every period of time that is defined as its half-life, decaying into its constituent products. Therefore, the mass of the radioactive substance after x half-lives is as follows:Mass = 0.5x x original mass.Using this formula, the original mass is 4.00g and the number of half-lives is 6 (9/1.5 = 6). We therefore have a mass of 4 x 0.56 g, which is equivalent to 1/16 of a gram.