I wasn't there, didn't observe the experiment, and haven't had the opportunity
to inspect the schematic diagram or review the circuit configuration. But if I had
to guess ... which I obviously do ... it would be my guess that EITHER each bulb
has its own individual battery or power supply, OR that both bulbs share the
same power supply and are connected to it in parallel.
You would place the convex lens between the lighted bulb and the screen, with the lighted bulb positioned beyond the lens's focal length. This arrangement will create an enlarged image of the lighted bulb on the screen due to the converging properties of the convex lens.
When the two electrodes contact, it completes the circuit, allowing the current to flow from one electrode to the other through the bulb. The current passing through the filament of the bulb causes it to heat up and emit light, resulting in the bulb lighting up.
When two electrodes are in contact with each other, they form a closed circuit that allows electricity to flow uninterrupted between them. This completes the circuit and provides a path for the electric current to flow from the power source, through the bulb, and back to the power source. This flow of electricity causes the bulb to light up.
When a bulb is lighted up, electrical energy is converted into light energy and heat energy. The electrical energy flows through the filament in the bulb, causing it to glow and emit light while also generating heat.
Electric bulb is basically an insulating device. By calling it an insulating device it does not mean that it completely disallows the flow of electricity! It means that the device or object resists the flow of electricity to some extent. It has a coil of a metal called Tungsten which resists the flow of electricity. Due to this resistance the coil heats up immensely and glows hot. However, this coil of Tungsten does allow some electricity to pass through so that the circuit of electrical flow remains closed/complete and the electric bulb remains lighted.
You break the circuit and they both extinguish (go out).Answer: The circuit will open up causing the current to quit flowing to both bulbs therefore there will be no lighted bulbsCommentYou also have the full supply voltage appearing across the empty lampholder!
if the one bulb is not lighted the all is no lighted
It would not be dangerous to leave a light bulb partially unscrewed, however, there is some possibility that it will fall out of the socket. I would advise that if you don't want the bulb to be on, and you don't have a light switch, unscrew the bulb completely and put it away until you need it.
You would place the convex lens between the lighted bulb and the screen, with the lighted bulb positioned beyond the lens's focal length. This arrangement will create an enlarged image of the lighted bulb on the screen due to the converging properties of the convex lens.
in bangalore
inspiration, or a bright idea
Parallel circuit
That is e.g. the resistance of a cold bulb before the bulb is lighted and heats up.
Chemical to radiant(light:)
The bulb "pulses" because the circuit is not completely off. If the CF bulb is pulsing or flashing, it means that there is some kind of feedback loop providing at least some voltage to the bulb. Often lighted switches use the filament resistance to provide voltage to the internal bulb. Get rid of the lighted switch.
do not touch alighted electric bulb conncted to the main
Without seeing the circuit involved no real answer can be given. I would guess you have a diagram of the circuit, tracing it out should answer your question.