because angle between r n F is zero, both r parallel.
Torque is proportional to the distance between the center and the line of force. Centripetal force acts toward the center along the radius, so the distance between the center and the line is zero. (When your car is up on the lift, you can't make a wheel rotate by pushing on the hub.)
A large force can produce a small or zero torque if the force is applied at a point where the lever arm (distance from the point of rotation to the line of action of the force) is very small or zero. Torque is calculated as force multiplied by lever arm, so a small lever arm can result in a small or zero torque even with a large force.
no because to get a torque you must multiply lever arm by force. If lever is zero, then torque is zero
The centripetal force always acts perpendicular to the displacement of the object moving in a circular path. Since the work done is the product of force and displacement in the direction of force, and the displacement is perpendicular to the centripetal force, the work done by the centripetal force over a full rotation is zero.
NO. not at all b/c torque is directly related to force
Torque is proportional to the distance between the center and the line of force. Centripetal force acts toward the center along the radius, so the distance between the center and the line is zero. (When your car is up on the lift, you can't make a wheel rotate by pushing on the hub.)
A large force can produce a small or zero torque if the force is applied at a point where the lever arm (distance from the point of rotation to the line of action of the force) is very small or zero. Torque is calculated as force multiplied by lever arm, so a small lever arm can result in a small or zero torque even with a large force.
no because to get a torque you must multiply lever arm by force. If lever is zero, then torque is zero
An object moves in a circle at constant speed. The work done by the centripetal force is zero because: 1. the displacement for each revolution is zero 2. the average force for each revolution is zero 3. there is no friction 4. the magnitude of the acceleration is zero 5. the centripetal force is perpendicular to the velocity
An object moves in a circle at constant speed. The work done by the centripetal force is zero because: 1. the displacement for each revolution is zero 2. the average force for each revolution is zero 3. there is no friction 4. the magnitude of the acceleration is zero 5. the centripetal force is perpendicular to the velocity
The centripetal force always acts perpendicular to the displacement of the object moving in a circular path. Since the work done is the product of force and displacement in the direction of force, and the displacement is perpendicular to the centripetal force, the work done by the centripetal force over a full rotation is zero.
In order for a force to produce a torque, either all of it, or a part of it (component) must act perpendicular to the moment arm. If, as in your case, all of the force is parallel to the moment arm then the force can not produce a torque. So the answer is; the torque is zero.
Yes true. But they need not be got cancelled though their resultant is zero.
NO. not at all b/c torque is directly related to force
Torque T=Nmsin x, thus Force N=T/msin x. If sin x is zero Torque is zero and Force is zero.
The work done by a centripetal force is zero because the force is always directed towards the center of the circular motion, while the displacement is perpendicular to the force. This means that the angle between the force and the displacement is 90 degrees, resulting in zero work being done.
A couple.