that depends on 3 factors, how big is the circle, how fast is the train, and how high is the ball thrown
also it is to be considered that u are assuming the natural (actual) conditions like the air thrust is present or hypothetical conditions that there is no air thrust.
Under all ideal conditions i.e. no air thrust etc. the ball will move tangentially to the path of the circle the train is traversing.
Yes, when a ball reaches the top of its trajectory when thrown vertically upward, it is momentarily at rest before gravity pulls it back down. This is a state of dynamic equilibrium because the forces acting on the ball are balanced at that point.
When a bullet is fired upwards vertically, it gains potential energy as it moves against gravity. This increase in potential energy comes at the expense of its initial kinetic energy. Eventually, the bullet will reach its maximum height and then begin to fall back towards the ground, converting its potential energy back into kinetic energy.
To come to rest, its velocity must change, therefore it will accelerate. Once it is at rest, if it remains at rest, it will no longer accelerate, i.e., its acceleration will be zero.
At the highest point of a ball's vertical motion, its velocity is zero. This is because the ball briefly comes to a stop before falling back down due to gravity.
When we throw the object upwards we consider that upward direction as positive. Therefore, the velocity in that direction is positive but the acceleration due to gravity is in the opposite direction and so it is considered negative. But when the ball comes down again after reaching a certain height the velocity is in opposite direction to the earlier one and so the velocity now is negative as a result the acceleration is again negative.
Yes, when a ball reaches the top of its trajectory when thrown vertically upward, it is momentarily at rest before gravity pulls it back down. This is a state of dynamic equilibrium because the forces acting on the ball are balanced at that point.
When a bullet is fired upwards vertically, it gains potential energy as it moves against gravity. This increase in potential energy comes at the expense of its initial kinetic energy. Eventually, the bullet will reach its maximum height and then begin to fall back towards the ground, converting its potential energy back into kinetic energy.
To come to rest, its velocity must change, therefore it will accelerate. Once it is at rest, if it remains at rest, it will no longer accelerate, i.e., its acceleration will be zero.
At the highest point of a ball's vertical motion, its velocity is zero. This is because the ball briefly comes to a stop before falling back down due to gravity.
When we throw the object upwards we consider that upward direction as positive. Therefore, the velocity in that direction is positive but the acceleration due to gravity is in the opposite direction and so it is considered negative. But when the ball comes down again after reaching a certain height the velocity is in opposite direction to the earlier one and so the velocity now is negative as a result the acceleration is again negative.
An example of when gravity slows down a moving object is when a ball is thrown upwards. As the ball moves against the force of gravity, it gradually loses speed until it comes to a stop at its highest point before falling back down. This decrease in speed is due to the gravitational force acting in the opposite direction to the ball's motion.
When a stone is thrown up in the air, it rises due to the initial force applied to it. However, gravity pulls the stone back down towards the Earth. As the stone loses its upwards momentum and the pull of gravity becomes stronger, it eventually falls back down to the ground.
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
because of the revolution of the earth.
The ball has the least kinetic energy at the highest point of its trajectory, when it momentarily comes to a stop before falling back down under the influence of gravity. At this point, all the initial kinetic energy from being thrown upwards is converted into potential energy due to the ball's height above the ground.
If you want the graph to show the acceleration of the ball against time, then the graph is a horizontal line. If you want the graph to show the velocity of the ball against time, then the graph is a straight line sloping downward. If you want the graph to show the height of the ball against time, then the graph is a parabola that opens downward.
it comes back to you