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Why when you hold a 5 kg mass at an angle of 10 degrees to the vertical do you exert much less force than when you hold it at 70 degrees?
The downwards force acting on the mass due to gravity will always be given by the mass of the object by the acceleration due to gravity. As this will not change due to the angle at which you hold it, you will have to exert the same force in both scenarios to hold the mass steady.
What else can I help you with?
A bolt needs to be tightened with a torque of 35 N-m You use a 25 cm wrench and pull at an angle of 60 degrees how much force do you need to exert?
To calculate the force needed to tighten the bolt, use the formula: Force = Torque / (Wrench length * sin(angle)) Force = 35 N-m / (0.25 m * sin(60 degrees)) Force = 141.42 N Therefore, you would need to exert a force of approximately 141.42 N to tighten the bolt.
How can a force be resolved in to rectangular components?
You would use trigonometry for that. If, for example, you have a force of magnitude 10 at an angle of 30 degrees: * The x-component is 10 times the cosine of 30 degrees * The y-component is 10 times the sine of 30 degrees Or better yet, learn to use the polar-->rectangular conversion on your scientific calculator.
A man pulls a 50 kilogram box 20 meters across the floor with the aid of a rope tied to the box The rope makes an angle of 30 degrees with the horizontal In pulling the box the man exerts a force of?
The man exerts a force of 245 Newtons to pull the box. This force can be calculated by resolving the force into its horizontal and vertical components. Given that the angle is 30 degrees, the horizontal component of the force can be found using trigonometry.
How much work you need to move a 280n shed to a platform 5 m above?
The work needed to move the shed to a platform 5m above would depend on the distance it needs to be moved horizontally and the method of moving it. The work done in lifting the shed against gravity can be calculated using the formula: work = force x distance x cos(angle), where the force is the weight of the shed (280 N), the distance is the vertical height (5m), and the angle is the angle between the force and the direction of movement (typically 0 degrees for vertical lifting).
What happen to the period and speed when thetha90 in conical pendulum?
When the angle is 90 degrees in a conical pendulum, the period becomes infinite and the speed approaches zero. This is because the vertical component of the tension in the string that provides the restoring force becomes zero at this angle, causing the motion to become unbounded.
A bolt needs to be tightened with a torque of 35 N-m You use a 25 cm wrench and pull at an angle of 60 degrees how much force do you need to exert?
To calculate the force needed to tighten the bolt, use the formula: Force = Torque / (Wrench length * sin(angle)) Force = 35 N-m / (0.25 m * sin(60 degrees)) Force = 141.42 N Therefore, you would need to exert a force of approximately 141.42 N to tighten the bolt.
Suppose you and your partner lift a bucket jointly the weight 50 Nthe angle between the your pulls in 90 degreeyour partner exert a force of 40 N .what is the force you exert?
You exert a force of 30 N.
If a force of 14 pounds is directed at an angle measuring 38 degrees from the horizontal of a right angle what will the horizontal and vertical components be?
Horizontal component = 14 cos(38) = 11.032 lbs (rounded)Vertical component = 14 sin(38) = 8.619 lbs (rounded)
How do you do a vertical jump lab report through the graph of trunk angle knee angle ankle angle jumping height and vertical force are provided?
angle of ( Q ) is the definition of starting strength
How can a force be resolved in to rectangular components?
You would use trigonometry for that. If, for example, you have a force of magnitude 10 at an angle of 30 degrees: * The x-component is 10 times the cosine of 30 degrees * The y-component is 10 times the sine of 30 degrees Or better yet, learn to use the polar-->rectangular conversion on your scientific calculator.
A 300 newton force acts on point c at an angle of twenty eight degrees what is the magnitude of the vertical?
(Cos30)300 = (0.883) 300 = 264.88 = 265 Nt.
When a ramp is at a angle of 10.5 degrees what will be the applied force?
The applied force will depend on the required force, and the angle to the ramp (or the horizontal) at which the force is applied.
A man pulls a 50 kilogram box 20 meters across the floor with the aid of a rope tied to the box The rope makes an angle of 30 degrees with the horizontal In pulling the box the man exerts a force of?
The man exerts a force of 245 Newtons to pull the box. This force can be calculated by resolving the force into its horizontal and vertical components. Given that the angle is 30 degrees, the horizontal component of the force can be found using trigonometry.
At what angle Work is minimum?
Work is minimized when the angle between the force applied and the direction of motion is 90 degrees (or π/2 radians). At this angle, the force does not contribute to the displacement in the direction of the force, resulting in zero work done. In general, as the angle increases from 0 to 90 degrees, the work done decreases, reaching its minimum at 90 degrees.
Dan applies a force of 92 N on a heavy box by using a rope held at an angle of 45 degrees with the horizontal. What are the vertical and horizontal components of the 92-N force?
The vertical component of the force is Fsin45 = 92 x 1/(2^1/2) = 65.2 The horizontal component of the force is FCos45 = 92 x 1/(2^1/2) = 65.2
What is the horizonatl and vertical components of a force vector projected at 63.7 degrees and with a speed of 73.78?
40
How much work you need to move a 280n shed to a platform 5 m above?
The work needed to move the shed to a platform 5m above would depend on the distance it needs to be moved horizontally and the method of moving it. The work done in lifting the shed against gravity can be calculated using the formula: work = force x distance x cos(angle), where the force is the weight of the shed (280 N), the distance is the vertical height (5m), and the angle is the angle between the force and the direction of movement (typically 0 degrees for vertical lifting).
