As a simple rule of thumb, sound travels at 1 mile every 5 seconds.
So, in 4 seconds, it has travelled 4/5 of a mile.
To be exact, it depends on the density of the air, which is determined by the altitude above sea level, the temperature of the air, and the relative humidty of the air (also know as the density altitude, a term used by pilots).
Using the formula distance = speed x time, we can calculate the distance the sound traveled as 340 m/s x 3.2 s = 1088 meters. Since the sound took 3.2 seconds to reach you, the rock must have fallen for 1.6 seconds (half the time) before you heard it. Using the kinematic equation h = (0.5 x acceleration x time^2), and assuming the rock fell straight down with an acceleration of 9.81 m/s^2, we find the height of the cliff to be about 25 meters.
Speed of sound is c ≈ 331 + 0.6 × T T = temperature in °C. Speed of sound at 30°C is c ≈ 331 + 0.6 × 30 = 349 m/s.
To find the frequency of a wave, you can use the formula: frequency = speed of the wave / wavelength. In this case, the speed of the wave is 340 m/s and the wavelength is 15 m. Plugging these values into the formula, the frequency of the wave is 340 m/s / 15 m = 22.67 Hz.
For a wavelengt lambda in air with the speed of sound of c = 340 meters per second the frequency f: f = c / lambda. A wavelength of 5 meters equals a frequency of 68 Hz. A wavelength of 0.2 meters equals a frequency of 1700 Hz. There is a useful calculator for converting wavelength to frequency and vice versa. Scroll down to related links and look at "Acoustic waves or sound waves in air".
It is different in different conditions. Generally it has 340ms-1 as the speed.
It was the same speed. It generally travel with 340ms-1 speed.
This is a low temperature. It travels in less than 340ms-1.
v = fλ V/f = λ (wavelength) V = 340ms-1 340/f = λ In short you need to know the frequency of the particular sound wave to work out it's wavelength. once you know that you plug it into the above equation and you will get the wavelength of the wave.
Using the formula distance = speed x time, we can calculate the distance the sound traveled as 340 m/s x 3.2 s = 1088 meters. Since the sound took 3.2 seconds to reach you, the rock must have fallen for 1.6 seconds (half the time) before you heard it. Using the kinematic equation h = (0.5 x acceleration x time^2), and assuming the rock fell straight down with an acceleration of 9.81 m/s^2, we find the height of the cliff to be about 25 meters.
That will not only depend on the temperature, but also on the exact composition of the air (such as, whether it is dry or humid), and possibly on the pressure. The typical speed of sound at 20 degrees C is approximately 343 meters/second.
Speed of sound is c ≈ 331 + 0.6 × T T = temperature in °C. Speed of sound at 30°C is c ≈ 331 + 0.6 × 30 = 349 m/s.
To find the frequency of a wave, you can use the formula: frequency = speed of the wave / wavelength. In this case, the speed of the wave is 340 m/s and the wavelength is 15 m. Plugging these values into the formula, the frequency of the wave is 340 m/s / 15 m = 22.67 Hz.
The speed of sound in air at 42.0°C is approximately 352 meters per second. As temperature increases, the speed of sound also increases in air due to the increased kinetic energy of the air particles.
The speed of sound is dependent on the temperature and not on the air pressure. At 20 degrees Celsius or 68 degrees Fahrenheit the speed of sound is 343 m/s or 1236.3 km/h or 1126.7 ft/s or 667.1 knots.Scroll down to related links and look at "Speed of sound - temperature matters, not air pressure".At room temperature (20°C, 68° F) the speed of sound is 343 meters per second, 767 miles per hour, or 0.213 miles per second.Sound waves must have matter and/or molecules to travel. Where there is no matter, such as in outer space, sound cannot travel.At room temperature (20°C, 68° F) the speed of sound is 343 meters per second, 767 miles per hour, or 0.213 miles per second.Sound waves must have matter and/or molecules to travel. Where there is no matter, such as in outer space, sound cannot travel.At 20 degrees Celsius the sound travels in air 343.4 meters per second. That means in 1 second the sound travels 343.3 meters. In 2.912 milliseconds the sound travels 1 meter.Well it is really dependent on the temperature of the air, but in this case we will assume the standard temperature ( 20 degrees C) it travels at 343 meters per second.Through air, sound waves travel at 343 m/s
Assuming that both notes are in the range of C4 (middle C) and C5, G has a frequency of 392Hz, and A has a frequency of 440Hz. Assuming that both sound waves are travelling through air, through which sound travels at 340ms-1, then the wavelengths for G and A can be found to be 0.87m and 0.77m, respectively.An easier way to assess a change in wavelength would be to look at the equation v=fλ, where v is the speed of sound, f is the frequency of the note, and λ is the wavelength of the note. A higher pitch note means a higher frequency, and since the speed of sound is constant, then if the pitch is increased the wavelength must compensate by decreasing.Simply put, higher pitch means smaller wavelength.
Assuming that both notes are in the range of C4 (middle C) and C5, G has a frequency of 392Hz, and A has a frequency of 440Hz. Assuming that both sound waves are travelling through air, through which sound travels at 340ms-1, then the wavelengths for G and A can be found to be 0.87m and 0.77m, respectively.An easier way to assess a change in wavelength would be to look at the equation v=fλ, where v is the speed of sound, f is the frequency of the note, and λ is the wavelength of the note. A higher pitch note means a higher frequency, and since the speed of sound is constant, then if the pitch is increased the wavelength must compensate by decreasing.Simply put, higher pitch means smaller wavelength.