square root of 3
tan(-60 degrees) = - sqrt(3)
1.732
- tan 60
Yes
The angle 300 degrees is in the fourth quadrant of the unit circle, where the tangent function is negative. Therefore, the sign of tan 300 degrees is negative. Specifically, tan 300 degrees can be calculated as tan(360 degrees - 60 degrees), which equals -tan(60 degrees), giving a negative value. Thus, tan 300 degrees is negative.
5400
Tan(60) = Sin(60)/ Cos(60) Sin(60) = sqrt(3)/2 Cos(60) = 1/2 Hence Sin(60) / Cos(60) = [sqrt(3) / 2] / [1/2} => sqrt(3) / 2 X 2/1 sqrt(3) Hence Tan(60) = sqrt(3) = Numerically = 1.732050808....
tan(pi/3) = tan (60 degrees) = 1.732 which is square root of 3
cot 115 deg = - tan25 deg
The exact value of 60 degrees would be 1/2. This is a math problem.
Other side = 60 tan 20, so area of rectangle = 3600 tan 20 = 3600 x 0.36397= 1310.29 sq ft
sin(60) or sin(PI/3) = sqrt(3)/2 cos(60) or cos(PI/3)=1/2 tan(60) or tan(PI/3) = sin(60)/cos(60)=sqrt(3) But we want tan for -sqrt(3). Tangent is negative in quadrant II and IV. In Quadrant IV, we compute 360-60=300 or 2PI-PI/3 =5PI/3 tan(5PI/3) = -sqrt(3) Tangent is also negative in the second quadrant, so we compute PI-PI/3=2PI/3 or 120 degrees. tan(t)=-sqrt(3) t=5PI/3 or 2PI/3 The period of tan is PI The general solution is t = 5PI/3+ n PI, where n is any integer t = 2PI/3+ n PI, where n is any integer