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The time required for one complete oscillation (or swing) of a pendulum is known as its period. The period of a simple pendulum depends on its length and the acceleration due to gravity. The formula to calculate the period of a pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.81 m/s^2).

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Q: What time required in 1 oscillation of pendulum?
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Related questions

How does the length of the pendulum effect the pendulum?

The longer the length of the pendulum, the longer the time taken for the pendulum to complete 1 oscillation.


What is the formula of time period for projection of particle?

time taken by pendulum/to complete 1 oscillation


Pendulum oscillation period is equal to 0.5 s What is the pendulum oscillation frequency?

T=1/f .5=1/f f=2


How many normal modes of oscillation or natural frequencies does a simple pendulum have?

simple pendulum would have 1 normal modes of oscillation or natural frequencies.


What are two factors that alter the oscillation period of a pendulum?

1. Length of the pendulum 2. acceleration due to gravity at that place


What are the physical parameters in the investigation of a simple pendulum?

The physical parameters of a simple pendulum include (1) the length of the pendulum, (2) the mass of the pendulum bob, (3) the angular displacement through which the pendulum swings, and (4) the period of the pendulum (the time it takes for the pendulum to swing through one complete oscillation).


What effect does decreasing the weight of the bob have on the period of the pendulum?

The weight of the bob will determine how long the pendulum swings before coming to rest in the absence of applied forces. The period, or time of 1 oscillation, is determined only by the length of the pendulum.


What is the time period of a pendulum which oscillates 40 times in 4 seconds?

Period of a pendulum (T) in Seconds is: T = 2 * PI * (L/g)1/2 L = Length of Pendulum in Meters g = Acceleration due to gravity = 9.81 m/s2 PI = 3.14 The period is independent of the mass or travel (angle) of the pendulum. The frequency (f) of a pendulum in Hertz is the inverse of the Period. f = 1/T


How is the period of the pendulum affected by its length?

the time period of a pendulum is proportional to the square root of length.if the length of the pendulum is increased the time period of the pendulum also gets increased. we know the formula for the time period , from there we can prove that the time period of a pendulum is directly proportional to the effective length of the pendulum. T=2 pi (l\g)^1\2 or, T isproportionalto (l/g)^1/2 or, T is proportional to square root of the effective length.


What is the period of a pendulum that takes 1 second?

The time that it "takes" is the period.


What is the relation between time period and frequency of oscillation?

Time period and frequency are mutual reciprocals. T = 1/f F = 1/t


How does length and initial angle affect the period in a simple pendulum?

The longer the pendulum is, the greater the period of each swing. If you increase the length four times, you will double the period. It is hard to notice, but the period of a pendulum does depend on the angle of oscillation. For small angles, the period is constant and depends only on the length of the pendulum. As the angle of oscillation (amplitude) is increased, additional factors of a Taylor approximation become important. (T=2*pi*sqrt(L/g)[1+theta^2/16+...] and the period increases. (see hyper physics: http://hyperphysics.phy-astr.gsu.edu/hbase/pendl.html) Interestingly, if the pendulum is supported by a very light wire then the mass of the object at the end of the pendulum does not affect the period. Obviously, the greater the mass, the less any air friction or friction at the pivot will slow the pendulum. Also interestingly, the pendulum period is dependant on the force of gravity on the object (g). One must not assume that g is constant for all places on Earth.