Well, honey, let me break it down for you. The number 7 appears on a digital clock 8 times in 24 hours. You've got it showing up as the hour digit twice (7 AM and 7 PM) and as the minute digit six times (07, 17, 27, 37, 47, 57). So, grab a clock and start counting those 7s!
Oh, what a happy little question! In a 24-hour day, the digit 7 will appear 8 times on a digital clock. You can find it in times like 07:07, 17:37, and 23:57. Just imagine those sevens dancing across the clock, bringing joy to each hour.
To determine how many times the number 5 appears on a digital clock in 24 hours, you can analyze each digit position (hours and minutes). The hours range from 00 to 23, where '5' appears once in the hour (05 and 15). For the minutes, '5' appears in every ten-minute interval (05, 15, 25, 35, 45, 55) for each hour, totaling 6 occurrences per hour. Combining these, '5' appears 2 times in the hour and 6 times in minutes for 24 hours, resulting in a total of 2 (from hours) + 6 x 24 (from minutes) = 146 occurrences.
#include<iostream> #include<array> #include<sstream> std::array<int,10> get_frequency (int range_min, int range_max) { if (range_max<range_min) std::swap (range_min, range_max); std::array<int,10> digit {}; for (int count {range_min}; count<=range_max; ++count) { std::stringstream ss {}; ss << count; std::string s {}; ss >> s; for (auto c : s) { ++digit[c-'0']; } } return digit; } int main () { std::array<int,10> digit {}; digit = get_frequency(1, 89); std::cout << "In the range 1 to 89...\n"; for (int d {0}; d<10; ++d) { std::cout << "\tthe digit " << d << " appears " << digit[d] << " times.\n"; } } Output: In the range 1 to 89... the digit 0 appears 8 times. the digit 1 appears 19 times. the digit 2 appears 19 times. the digit 3 appears 19 times. the digit 4 appears 19 times. the digit 5 appears 19 times. the digit 6 appears 19 times. the digit 7 appears 19 times. the digit 8 appears 19 times. the digit 9 appears 9 times.
many times.
158 In every hour of the day except 7 am and 7 pm the digit 7 appears on the clock 6 times. you take 2 hours (7am and 7pm) out of 24 hours and the rest are 22 hours. Then 22 hours multiply x 6 because in each of the 22 hours 7 appears 6 times, 22 x 6 makes 132. The remaining 2 hours from 24 are 7am and 7pm, 7 appears 13 times in each of these hours; 7:00, 7:07, 7:17, 7:27, 7:37, 7:47, 7:57. Then you do 13 x 2 because there are 2 7:00 (am and pm), you get 26. Now the total of 132 from 22 hours and 26 from the other 2 hours brings the total of 158; 132+26=158, our final answer is 158. so in 24 hours the digit 7 appears in 158 different times on a digital clock. By: Ahmad J. I.S.303 class 8-326.
The digit 1 appears 301 times, as opposed to 300 for the digits 2 to 9.
1:11
11 times
The number 5 appears 12 times on a 24-hour digital clock. It appears once in the hour (05:00, 15:00) and once in the minutes for each hour from 00 to 23 (e.g., 00:05, 01:05, ..., 23:55), resulting in 10 occurrences in the minutes. Therefore, the total is 2 (from the hours) + 10 (from the minutes) = 12.
To find the number of times the digit '3' appears in the given string of numbers, we can count the occurrences. The digit '3' appears 64 times in the provided sequence.
The first digital alarm clock was invented in 1956 by D.E. Protzmann, an engineer at General Electric. This alarm clock featured a digital display and the ability to set specific alarm times, setting the foundation for modern digital alarm clocks.