1/11/2011. January 11th,2011.
1111
it mean 13/117 so the answer would be .1111
Do the math: •9 AM Wed-9 AM Fri=48 hours •9 AM Fri-10 PM Fri=13 hours •48+13=61 So the answer is 61 hours. :)
1 + 1,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111 = 1,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,111,112 Unless it is binary, in which case: 1 + 111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 1111 11111 1111 1111 1111 1111 = 1000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000
15 = 1111 14 = 1110 13 = 1101
1, 11, 13, 101, 143, 1111, 1313 and 14443
110/130 and 1111/1313 are two.
There were two. They were in September and December.
For that to happen, the month has to be 31 days long and has to start on a Friday. Since there are 7 months with 31 days and one chance in 7 a month will start on a Friday ( roughly, due to leap years) there is about once yaer this will happen.Next month has 5 Fridays, Saturdays, and Sundays.Since14.5% of all years have a January with 5 of (Fri-Sat-Sun),14.25% of all years have a March with 5 of (Fri-Sat-Sun),14.5% of all years have a May with 5 of (Fri-Sat-Sun),14.5% of all years have a July with 5 of (Fri-Sat-Sun),14.25% of all years have an August with 5 of (Fri-Sat-Sun),14% of all years have an October with 5 of (Fri-Sat-Sun), and14% of all years have a December with 5 of (Fri-Sat-Sun),the average occurrence comes to exactly once per year.
39% of 1111= 39% * 1111= 0.39 * 1111= 433.29
(7777-6666)/1111 = 1 (4444+5555)/(9999/3333) = 3 8888/2222 = 4 4*3 + 1 =13
The factors of 1111 are: 1, 11, 101, 1111.