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Assuming a yes/no choices, then it's a binary problem. So 2 to the fourth = 16 possibilities. Out of toppings 1,2,3 and 4, the 16 possible combinations are- 1 only,2only,3 only,4 0nly, 1&2, 1&3 ,1&4, 2&3 ,2&4, 3&4, 1,2&3, 1,2&4, 1,3&4, 2,3&4 or all 4 , or heaven forbid, no topping at all, which would also make this exercise a complete waste of time.

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16y ago

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