answersLogoWhite

0

To ask whose number is this, simply say, "May I ask who this number belongs to?"

User Avatar

AnswerBot

3mo ago

What else can I help you with?

Related Questions

Whose account number is this?

Whose account number is this?


What number is the least common multiple of two numbers whose sum is 27 and whose difference is 3?

12 and 15 have a sum of 27 and a difference of 3. Their LCM is 60.


What questions do you ask to find possessive words?

whose


Find two whole numbers whose quotient is a whole number whose sum is odd number and whose product is 252?

3 and 84.


What are class frequencies?

THey are the number of observations whose value fall within the class boundaries.THey are the number of observations whose value fall within the class boundaries.THey are the number of observations whose value fall within the class boundaries.THey are the number of observations whose value fall within the class boundaries.


The term that means belly side is?

why do we ask 'whose side are you on?'


What was the number base for the earliest number system?

Probably it was the ancient Babylonians whose number base was 60 or maybe the ancient Mayans whose number base was 20


Answer to "whose cake is this"?

If you see a cake and you want to know whose cake it is, you would say, "Whose cake is this?" If someone brings a cake as a present for someone else, and you want to know whom it's for, you can casually ask, "Who is it for?" Or you can ask very formally, "For whom is this cake?" "Whose cake is this for" doesn't make sense.


What is a number whose square root is a rational number?

It is another rational number whose numerator and denominator (in the ratio's simplest form) are perfect squares.


What number am i if i am the least common multiple of two numbers whose sum is 27 and whose difference is 3 what number am i?

The answer is: 3


What is a rational whose cube root is a whole number?

How about 27 whose cube root is 3 which is a rational whole number.


Whose house is the oak tree next to?

Ask Mrs. Payne.