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What is the percentage of people that pass their HT ASCP exam on the first try?
Wiki User
∙ 12y ago
64% according to Histonet.
Wiki User
∙ 12y ago
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A student writes 2 exams and gets 83 percent for the first and 90 percent for the second The second exam counts for 66 percent of the overall result What is his final percentage?
Answer:87.62 %Solution:given: Second exam weight = 66%then: overall weight = 100% this is conclusion from the question.the first exam weight = 100-66= 34%Final result = weighted average =(first exam result * weight of first exam + second exam reuslt * weight of second exam) / Overall weight= (83*34+90*66)/100=(2822+5940)/100= 8762/100= 87.62%---More information about weighted mean:http://en.wikipedia.org/wiki/Weighted_mean
