75
An eighth remains.
8
You find the sample space by enumerating all of the possible outcomes. The sample space for three coins is [TTT, TTH, THT, THH, HTT, HTH, HHT, HHH].
The sample space when tossing a coin three times is [HHH, HHT, HTH, HTT, THH, THT, TTH, TTT]It does not matter if you toss one coin three times or three coins one time. The outcome is the same.
125
After each half-life, the number of undecayed nuclei is halved. Starting with 600 nuclei, after one half-life, 300 would remain; after the second half-life, 150 would remain; and after the third half-life, 75 would remain. Thus, after three half-lives, 75 undecayed headsium nuclei would remain in the sample.
Approx 1/8 will remain.
Not sure what you mean by "had-lives". After 3 half lives, approx 1/8 would remain.
An eighth remains.
It will take two half-lives or about 60.34 years for three-fourths of a Cs-137 sample to decay.
To determine the remaining amount of a 200 gram sample after 36 seconds with a half-life of 12 seconds, we first calculate how many half-lives fit into 36 seconds. There are three half-lives in 36 seconds (36 ÷ 12 = 3). Each half-life reduces the sample by half: after the first half-life, 100 grams remain; after the second, 50 grams; and after the third, 25 grams. Therefore, 25 grams of the sample would remain after 36 seconds.
After three half-lives, only 1/8 (or 12.5%) of the original radioactive sample remains. This is because each half-life reduces the amount of radioactive material by half, so after three half-lives, you would have (1/2) * (1/2) * (1/2) = 1/8 of the original sample remaining.
1/8 of the original amount remains.
If I take a radioactive sample of 400 moles of an unknown substance and let it decay to the point of three half-lives I would have 50 moles left of the sample. 1/2 of what is left will decay in the next half-life. At the end of that half-life I will have 25 moles left of the unknown substance or 4/25.
If the half-life of bromine is 25 minutes, than in 75 minutes three half lives would have passed. If you started with a 4.0 mg sample, than after three half-lives only 0.50 mg would remain. Because you are dealing with a whole number of half lives, all you have to do is divide 4.0 by 2 three time. Alternatively, you could multiply 4.0 by one half raised to the third power. This would look like this when entered into a calculator: 4.0 X (0.5^3) = 0.5
Not sure what you mean by "had-lives". After 3 half lives, approx 1/8 would remain.
Three half lives have elapsed. This can be determined by calculating how many times the original sample size must be halved to get to one eighth: (1/2) * (1/2) * (1/2) = 1/8.