First, you probably need more than one raw score. If you only have one raw score then your range is one point, the (score - 1/2) to the (score + 1/2). For a score of 80, the range would be from 79.5 to 80.5. It is kind of meaningless if you find a range for just one score. You need a larger sample size. A better question is: "How do I find the range of a sample of raw scores?" You need all of the raw scores in your sample, not just one score. Because each whole number (i.e., 80) represents a continuum (e.g., of ability), the range goes from 1/2 a point below the lowest score to 1/2 a point above the highest score. Let's look at some fake data with 5 participants: 10 20 30 40 50. The highest score is 50. The lowest score is 10. The range is (10-.5) to (50+.5). The range of raw scores is 9.5 to 50.5, a range of 41 points. If you are looking for the easy answer, then the range is 10 to 50 (lowest score to highest score; a range of 40 points). If you for some reason only have one score (e.g., 80), the long answer is 79.5 to 80.5 (range of one), the short answer is that there is no variability (range of zero).
There is insufficient information in the question to answer it. To determine Z-Score, you need raw score, which you gave, but you also need mean and standard deviation, which you did not give. Please restate the question.
z = (x - μ) / σ is the formula where x is the raw score and z is the z-score. μ and σ are the mean and standard deviations and must be known numbers. Multiply both sides by σ zσ = x-μ Add μ to both sides μ + zσ = x x = μ + zσ You calculate the raw score x , given the z-score, μ and σ by using the above formula.
Let your raw score be x and M the mean and S the standard deviation. The Z score for your specific x is Z=(x-M)/S So say your score is 80 (out of 100) and the mean is 70 and the standard deviation is 10. Then the z score for your 80 is: (80-70)/10=1 If on the other hand you got a 60, then the z score would be -1.
This question cannot be answered. You need the mean and standard deviation in order to compute a Z score for a Raw score. Please restate the question.
There is insufficient information in the question to answer it. To determine Z score, you need raw score, mean, and standard deviation. Please restate the question.
To find the mean from a raw score, z-score, and standard deviation, you can use the formula: ( \text{Raw Score} = \text{Mean} + (z \times \text{Standard Deviation}) ). Rearranging this gives you the mean: ( \text{Mean} = \text{Raw Score} - (z \times \text{Standard Deviation}) ). Simply substitute the values of the raw score, z-score, and standard deviation into this formula to calculate the mean.
Yes.z = (raw score - mean)/standard error.Since the standard error is positive, z < 0 => (raw score - mean) < 0 => raw score < mean.
Yes.
A GRE raw Score is the number of questions you answered correctly.
A GRE raw Score is the number of questions you answered correctly.
Go back to the basic data, estimate the sample mean and the standard error and use these to estimate the Z-score.
The raw score is any value that is observed.
If the Z Score of a test is equal to zero then the raw score of the test is equal to the mean. Z Score = (Raw Score - Mean Score) / Standard Deviation
To convert a raw score into a T-score, you first need the mean and standard deviation of the raw scores. The T-score is calculated using the formula: ( T = 50 + 10 \times \frac{(X - \text{Mean})}{\text{SD}} ), where ( X ) is the raw score, Mean is the average of the raw scores, and SD is the standard deviation. This transformation standardizes the score, placing it on a scale where the average is 50 and the standard deviation is 10.
There is insufficient information in the question to answer it. To determine Z-Score, you need raw score, which you gave, but you also need mean and standard deviation, which you did not give. Please restate the question.
No.
Raw mushrooms have an ANDI score of 135.