50%
Assuming that boys and girls are equally likely, it is 11/16.
50-50
In a family with four children, the probability of having four boys is 1 in 16.
there is a 50% chance that two of them will be girls
1 in 2
Assuming that boys and girls are equally likely, it is 11/16.
50-50
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
To determine the probability of selecting a family with exactly 3 male children out of 4, we can use the binomial probability formula. The probability of having a male child is typically considered to be 0.5 (assuming an equal likelihood of male and female). The probability of exactly 3 males in 4 children is calculated as ( P(X = 3) = \binom{4}{3} (0.5)^3 (0.5)^1 = 4 \times 0.125 \times 0.5 = 0.25 ). Thus, the probability is 0.25 or 25%.
In a family with four children, the probability of having four boys is 1 in 16.
1 in 64
We would need to know the number of children in the family to answer this question. For instance, the probability of having no girls in a family of two children would be 1/4 theoretically. In general it is 2-n where n is the number of children.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. A family of 4 is a family of two parents and two children. The probability that both children are girls is 0.2334
The probability of a boy is still 0.5 no matter how many prior children there are.
The probability of having 2 boys and 1 girl in a family with three children can be calculated using the binomial probability formula. Assuming the probability of having a boy or a girl is equal (1/2 each), the probability of having 2 boys and 1 girl can be found by considering the different combinations (BBG, BGB, GBB). Therefore, the probability is ( \frac{3}{8} ) or 37.5%.
there is a 50% chance that two of them will be girls
It is 3/8.