To determine the probability of different offspring from the cross of genotypes BB, Bb, and bb, we first need to clarify the specific cross being made. If we are crossing BB (homozygous dominant) with Bb (heterozygous), the potential offspring would be 50% BB and 50% Bb. If we then cross this with bb (homozygous recessive), the resulting offspring would be 50% Bb and 50% bb. Thus, the probabilities for the offspring would be 50% Bb and 50% bb.
The hybrid is the offspring so the probability is 1.
We would need to know the situation to respond to this question.
If you want to ask questions about something that is "shown", then I suggest that you make sure that there is something that is shown.
there is a 50% chance that the offspring will be tall.
100%
In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.
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It is important to remember that the factors inherited by the first offspring of a cross have no effect at all on other offspring of that cross. For example, there is a 25% probability that offspring of a cross betweet two hybrid bean plants will inherit the factos RR. If one offspring inherits RR, there is still a 25% probability that the next offspring will also inherit RR.
The offspring in the first column both have two dominant T alleles. Therefore, you know that the father (parent on the left hand side) is TT and the mother (parent on the top) has a dominant T in that column too. The offspring in the second column are Tt. The dominant T came from the father, as figured out in the first part of the problem. The recessive allele t came from mother's second empty box.
The Punnett square is a diagram that is used to predict the outcome of a particular cross or breeding experiment. It is used by biologists to determine the probability of an offspring having a particular genotype.
The hybrid is the offspring so the probability is 1.
No, there are more than two possible genotypes among the offspring when both parent genotypes are Aa. The potential genotypes for the offspring are AA, Aa, and aa, resulting in a total of three different genotypes. The expected ratio from a Punnett square for this cross is 1 AA : 2 Aa : 1 aa.
A Punnett square shows all possible outcomes of a genetic cross between male and female organisms. It is a visual tool used to predict the probability of different genotypes and phenotypes in offspring based on the genotypes of the parents.
100% of the offspring in a cross between parents with the genotypes EE and EcEc will exhibit cataracts, as all their offspring will inherit at least one copy of the cataract-causing genotype, Ec.
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
To perform a Dihybrid cross, you first need to identify the genotype of both parent organisms. Then, create a Punnett square to predict the genotypes of their offspring. Finally, analyze the resulting genotypes to determine the possible phenotypic ratios of the offspring.
You could cross breed them and depending on what their offspring is, you can determine what their genotype is.