Probability

If a normal die is rolled once, the outcomes are {1, 2, 3, 4, 5, 6}.

Unseen money or "no money at all"

Assuming that you are considering a N(0,1) Gaussian distribution, the answer is approximately 1 in 20. The 0.95%ile (two tailed) occurs at -1.96 and 1.96.

3

Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of

randomly selecting the vowel letter 'a' is P(v) = 1/4.

Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of

randomly selecting a vowel letter is P(v) = 2/5.

The probability of randomly selecting a vowel letter from the first word and a vowel

letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%

50-50

President

Sports PLayer

Army

Al QADA

TWO

Assuming that the colors are balanced, the probability is 1 in 5.

Time-Probability Graph

Denote by mu the mean of X. Given

P(X>5.52)=0.305

i.e.,

P((X-mu)/4> (5.52-mu)/4)=0.305

So, letting Z=(X-mu)/4. Then Z~N(0,1). Hence, the above equality is

P(Z>(5.52-mu)/4)=0.305. So,

(5.52-mu)/4=0.51

So,

mu=5.52-4*0.51=3.48

So, the best answer is 3.5

513

0 (there is no chance it will be short since tall is dominant over short).

Hope this helps!

- Biology Student

Since the numbers (number of dots) on normal dice only go from 1 - 6, then I would think the probability of getting the number 100 is zero.

There are 6 different doubles that can be rolled. (They are 1 and 1, 2 and 2, etc.) You have a 6/36 chance of rolling doubles. The fraction 6/36 simplifies (reduces) to 1/6. Your 1 in 6 chance of rolling doubles now needs to be converted to probability. Probability speaks to the "chance" that something will occur. It is expressed as a "pure" number, and the range of probability is from 0 to 1. The probability 0 means that it cannot occur, and the probability 1 means that it will or must occur. Everything else falls in between. If you have a 1 in 6 chance of rolling doubles that translates into a 1 divided by 6 probability, or a 0.1666666... probability that a double will come up.

If probability becomes greater than one, then the uncertainty coefficient fluctuates and results in a terminal case.

The answer would be 2/11 plus 1/2. Whatever that is.

Let A = rolling a double Let B = sum is 11 P(A)=6/36=1/6 P(B)=2/36=1/18 since (5,6) and (6,5) produce a sum of 11. We want to find P(A/B)= P(A & B) / P(B) = 0 / P(B)=0 P(A & B) represent the event getting a double and the sum being 11.

please help!

A 50% to 50% chance (half to half).

The probability is 1/6 x 5=5/12

1/2 Because there is one side with heads (1/) and the total sides (/2)

There are eight possible results when flipping three coins (eliminating the highly unlikely scenario of one or more coins landing on their edge): Dime - Heads / Nickel - Heads / Penny - Heads Dime - Heads / Nickel - Heads / Penny - Tails Dime - Heads / Nickel - Tails / Penny - Heads Dime - Heads / Nickel - Tails / Penny - Tails Dime - Tails / Nickel - Heads / Penny - Heads Dime - Tails / Nickel - Heads / Penny - Tails Dime - Tails / Nickel - Tails / Penny - Heads Dime - Tails / Nickel - Tails / Penny - Tails

A company is studying the number of daily debit card purchases. If there were 20 purchases and the probability of a debit card purchase is 0.5

What is the shape of this distribution

A three digit number can be chosen in 9*10*10 = 900ways

No. of ways to choose a three digit number without 7 is 8*9*9 = 648 ways

probability of picking a three digit number that includes atleast one digit that is 7 is 1- (648/900) = 252/900 = 7/25