Probability

A biased probability is one where not every outcome has the same chance of occurring. A biased coin is one where one side, the "heads" or "tails" has a greater probability than the other of showing.

A coin which has a centre of gravity closer to the tails side than the heads side would be biased in that heads is more likely to show than tails.

The size of coin can have an effect on the probability of heads and tails - during the Royal Institute Christmas lectures in the 1990s demonstrating probability a large version of the pound coin was made to be able to allow the audience to see it being tossed - on the broadcast (and tape) version it landed and stayed on its edge! showing the probability of heads = tails ≠ ½; the probability of heads = probability of tails, but they are actually slightly less than ½ as the coin could land on its edge and stay there - with a standard size coin, if it lands on its edge it takes very little for the centre of gravity to shift outside the base of the edge and for the coin to fall over, but with a very large similar coin (ie one scaled up [proportionally] in lengths) it can take quite a bit before the centre of gravity goes outside the base if it lands on its edge which forces it to fall over (plus there will be a "significant" rise in the centre of gravity to do so, thus favouring stability on an edge which does not exist in the standard, small, sized version of the coin).

It is 3/13.

The standard deviation is sqrt[n*p*(1-p)] = sqrt(1000*0.94*0.06) = 7.51 approx.

The months that end in y are January, February, May, and July. Two of those four start with J. So 2/4=.5 is the answer.

For a continuous variable it is 0.5 but for a discrete variable the answer depends on the probability of the variable taking the mean value. It is half of the rest of the probability.

If the discrete variable X has mean m and Prob(X = m) is p

then Prob(X > m) = (1 - p)/2.

The odds are 1 to 25.

Examples like the propability for raining tommorrow will 1/2 may or may not happen probability is called possibility

When a fair die is thrown the probability that a prime number will occur is 2:1

1 in 6 = rolling a 2

5 in 6 = not rolling a 2

There are 4! or factorial(4) = 24 ways.

There are 30 ways.

Probabilistic is the adjective form of probability.

incident complexity

The answer depends on where in the world the random selection is taken since the location will determine the mix of cars that the selection is made from.

Considering that a this is a six-faced die, the probability or rolling a 5 or 6 is 2/6. Or to simplify it, 1/3. This is because there are six sides, and you want to get two out of the six sides.

These are independent events; neither one depends on the results of the other.

The answer will depend on what numbers are on the wheel, what the variable is (the sum, product or some other function of the individual spins). Since there is no information on these factors, the question cannot be answered.

If you roll them often enough then the probability is 0. For just one roll, the probability is 35/36.

Recall that probabilty is the quotient of specific outcome divided by all outcomes. This is a relatively small problem to enumerate, so here goes...

1 + 1

2 + 1

3 + 1

4 + 1 = 5

5 + 1

6 + 1

1 + 2

2 + 2

3 + 2 = 5

4 + 2

5 + 2

6 + 2 = 8

1 + 3

2 + 3 = 5

3 + 3

4 + 3

5 + 3 = 8

6 + 3

1 + 4 = 5

2 + 4

3 + 4

4 + 4 = 8

5 + 4

6 + 4

1 + 5

2 + 5

3 + 5 = 8

4 + 5

5 + 5

6 + 5

1 + 6

2 + 6 = 8

3 + 6

4 + 6

5 + 6

6 + 6

You can see that the number of instances of the parent set is 36, while the number pf omstamces of the desired set is 9. As a result the probability of throwing a 5 or 8 with two dice is 9 in 36, or 1 in 4, or 0.25.

Odds of rolling ONE six - 6:1

Odds of rolling TWO sixes - 36:1

Odds of rolling two sixes, SIX times - 216:1

Assess hazards

Not sure about the "best" definition. It is the set of all possible outcomes for the event.